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1. 12.992 L
2. 2.42 moles
3. 275.52 L
4. 567.844 g
<h3>Further explanation</h3>
Given
moles and volume at STP
Required
mass, volume and moles
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
1. 0.58 moles ammonia :
Volume = 0.58 moles x 22.4 L = 12.992 L
2. 77.5 grams of O₂ :
Moles = 77.5 grams x (1 mol/32 grams) = 2.42
3. 12.3 mole of Bromine gas :
Volume = 12.3 mole x (22.4 L/1 mole) = 275.52 L
4. 4.8 moles iron(II)chloride :
Mass = 4.48 moles x molar mass ( 126,751 g/mol) = 567.844 g
Answer:
Check the explanation
Explanation:
cell CuE Ecell 0.337 (-0.14) Ecl0.477 V
Since 
, the value of \Delta G^o will be negative.
.....(1)
But
......(2)
From (1) and (2)
ln K =
ln K =
ln K =37.139
K =
Hence, the value of the equilibrium constant is 
Answer:
39.0983.
Explanation:
you are converting between grams Potassium and mole. You can view more details on each measurement unit: molecular weight of Potassium or mol The molecular formula for Potassium is K. The SI base unit for amount of substance is the mole.
