Bohr's model explained the position of the electron, proton, and neutron in the atom of the element. The energy at the n = 2 level of the atom will be - 3.40 eV.

<h3>What is the principal quantum number (n)?</h3>

The principal quantum number (n) has been the distance of the electron of that atom in the nucleus and its energy in the structure. It can also be said to define the size of the atomic orbit.

n = 2 is the first excited state whose energy is calculated as:

Eₙ = − 13.6 ÷ n² eV

E₂ = - 13.6 eV ÷ 2²

= -3.40 eV

Therefore, -3.40 eV is the energy of electron at n = 2.

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7 0

2 years ago

Kinetic Energy Problems = KE = 0.5m x 12

Brut [27]

Explanation:

The kinetic energy of an object is given by :

$K=\dfrac{1}{2}mv^2$

1. Mass, m = 5 kg

Speed, v = 2 m/s

$K_1=\dfrac{1}{2}\times 5\times (2)^2\\\\=10\ J$

2. Mass, m = 71 kg

Speed, v = 1 m/s

$K_2=\dfrac{1}{2}\times 71\times (1)^2\\\\=35.5\ J$

3. Mass, m = 71 kg

Speed, v = 5 m/s

$K_3=\dfrac{1}{2}\times 71\times (5)^2\\\\=887.5\ J$

4. Mass, m = 1816 kg

Speed, v = 25 m/s

$K_4=\dfrac{1}{2}\times 1816\times (25)^2\\\\=567500\ J$

8 0

3 years ago

if the same amount of heat is added to 50.0 g samples of each of the metals, which are all at the same temperature, which metal

Salsk061 [2.6K]

The metal which will reach the highest temperature is the metal with the lowest specific heat capacity.

<h3>What is the amount of heat added to each metal?</h3>

The amount of heat Q = mcΔT where

m = mass of metal
c = specific heat capacity of mateal and
ΔT = temperature change

<h3>Temperature change of the metal</h3>

Making ΔT subject of the formula, we have

ΔT = Q/mc

Given that Q and m are the same for each metal,

ΔT ∝ 1/c

We see that the temperature change is inversely proportional to the specific heat capacity.

Since the metals are at the same temperature, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.

So, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.

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6 0

2 years ago

Sixty liters of a gas were collected over water when the barometer read 663 mmhg , and the temperature was 20∘c. what volume wou

lesya [120]

First, let's compute the number of moles in the system assuming ideal gas behavior.

PV = nRT
(663 mmHg)(1atm/760 mmHg)(60 L) = n(0.0821 L-atm/mol-K)(20+273 K)
Solving for n,
n = 2.176 moles

At standard conditions, the standard molar volume is 22.4 L/mol. Thus,

Standard volume = 22.4 L/mol * 2.176 mol =<em> 48.74 L</em>

3 0

4 years ago