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NeX [460]
3 years ago
13

A substance that speeds up the rate of a chemical reaction is called

Chemistry
2 answers:
NeTakaya3 years ago
8 0
I'm not going toblie I'm stuck with A and B. But to me my gut says A
Nostrana [21]3 years ago
6 0
A substance that speeds up the rate of a chemical reaction is called a catalyst. As a catalyst speeds up the reaction, as an enzyme does. <span />
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What is the molecular formula for Tricarbon nonachloride?
vampirchik [111]

Answer:

C_{3}Cl_{9}

Explanation:

Molecular Formula is representation of the chemical compound in terms of the symbols of all the elements that are present in the compound followed by subscripts, which give the count of each element in that compound.

We need to write the molecular formula of Tricarbon nonachloride. Tri means three, so Tricarbon means there are 3 atoms of Carbon. Likewise, nona stands for 9, so nonachloride means there are 9 atoms of chlorine. Therefore, we can represent nonachloride as:

Carbon (3 atoms) Chlorine (9 atoms) = C_{3}Cl_{9}

Thus, molecular formula of Tricarbon nonachloride is C_{3}Cl_{9}

8 0
3 years ago
Read 3 more answers
What is the molarity of a solution which contains 0.88 g of barium chloride in 120.0 mL of solution
Andre45 [30]

Answer:00.73

Explanation:

Divide 0.88g by 120.0ml

6 0
3 years ago
1 point
jekas [21]
I’m pretty sure it’s density :)
4 0
3 years ago
In an atom, where are electrons with less energy most likely located
Marianna [84]
Please let me know when you find out, i need this question answered as well
4 0
3 years ago
The specific heats and densities of several materials are given below: Material Specific Heat (cal/g·°C) Density (g/cm3) Brick 0
abruzzese [7]

<u>Answer:</u> The change in temperature is 84.7°C

<u>Explanation:</u>

To calculate the change in temperature, we use the equation:

q=mc\Delta T

where,

q = heat absorbed = 1 kCal = 1000 Cal    (Conversion factor: 1 kCal = 1000 Cal)

m = mass of steel = 100 g

c = specific heat capacity of steel = 0.118 Cal/g.°C

\Delta T = change in temperature = ?

Putting values in above equation, we get:

1000cal=100g\times 0.118cal/g^oC\times \Delta T\\\\\Delta T=\frac{1000cal}{100g\times 0.118cal/g^oC}\\\\\Delta T=84.7^oC

Hence, the change in temperature is 84.7°C

5 0
3 years ago
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