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3 years ago

Stephan claims that Earth has both a gravitational field and a magnetic field. Which statement best supports his claim?

Chemistry

1 answer:

Bess [88]3 years ago

5 0

Answer:

Explanation:

Without gravity, any object wont go to the ground, and without a magnetic field, a compass cant be used for navigation.

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A temperature increase causes the particles to what ??!

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To move around more. bounce off walls ect. they are more energised

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2 years ago

Which of the following vertebrates evolved in the Carboniferous period?

topjm [15]

Reptiles arose during the Carboniferous period. Therefore making the answer Reptiles

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2 years ago

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What are two examples of a chemical change

lyudmila [28]

Answer:

1.Cooking an egg

2. Burning wood

Hope it helps :)

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2 years ago

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Consider the reaction N2(g) + 2O2(g)2NO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr

zysi [14]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$N_2+2O_2\rightarrow 2NO_2$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(NO_2(g))})]-[(1\times \Delta S^o_{(N_2(g))})+(2\times \Delta S^o_{(O_2(g))})]$

We are given:

$\Delta S^o_{(NO_2(g))}=240.06J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(N_2)}=191.61J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (240.06))]-[(1\times (191.61))+(2\times (205.14))]\\\\\Delta S^o_{rxn}=-121.77J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-121.77) J/K = 121.77 J/K

We are given:

Moles of nitrogen gas reacted = 1.90 moles

By Stoichiometry of the reaction:

When 1 mole of nitrogen gas is reacted, the entropy change of the surrounding will be 121.77 J/K

So, when 1.90 moles of nitrogen gas is reacted, the entropy change of the surrounding will be = $\frac{121.77}{1}\times 1.90=231.36 J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of nitrogen gas is reacted is 231.36 J/K

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3 years ago

Water vapor turning to frost is an example of __________.

Oksi-84 [34.3K]

Deposition is the correct answer if I believe so

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2 years ago

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