PH=-log[H⁺]
pH=-log(1.87×10⁻¹³)
pH=12.72
I hope this helps. Let me know if anything is unclear.
The scientist should make a new hypothesis and do a new experiment! That is what I say!
Answer:

Explanation:
Hello!
In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

Then, given the molarity, it is possible to obtain the milliliters as follows:

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Answer:
4
Explanation:
there is a decimal place present. so you would take away any zeros before the number.
1.Calculate the number of mole of O2: 48/32=1.5 mol
2.Calculate the number of mole of H2 by mole ratio: 1.5 x 1/2=0.75 mol
3.Calculate the answer:
0.75 x 2=1.5g