Question

How many zero pairs must be added to the function

Answer 1

Answer:

There is only one zero pair added i.e. 9.                                          

Step-by-step explanation:

Given : Function $f(x)=x^2-6x+1$

To find : How many zero pairs must be added to the function  in order to begin writing the function in vertex form?  

Solution :

Converting the given function into vertex form,

$f(x)=x^2-6x+1$

Adding and subtracting square of 3,

$f(x)=x^2-6x+(3)^2-(3)^2+1$

Square form as $a^2-2ab+b^2=(a-b)^2$

$f(x)=(x-3)^2-9+1$

$f(x)=(x-3)^2-8$

So, The required vertex form is $f(x)=(x-3)^2-8$

There is only one zero pair added i.e. 9.

Answer 2

(3,-8) that the answer