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3 years ago

How will a current change if the voltage in a circuit is held constant while the resistance doubles?

Physics

1 answer:

VARVARA [1.3K]3 years ago

5 0

<h2>Answer:</h2>

The current will drop to half of its original value.

<h2>Explanation:</h2>

To solve this problem, we must use Ohm's law that states that in a circuit the voltage $v$ across a resistor is directly proportional to the current that flows through that circuit. In other words:

$v \propto Ri \\ \\ or: \\ \\ v=Ri \\ \\ It's \ also \ valid: i=\frac{v}{R}$

According to our problem, if the voltage in the circuit is held constant while the resistance double, that is $R_{New}=2R \ and \ v_{New}=v$ . So:

$v=R_{New}i_{New} \\ \\ v=2Ri_{New} \\ \\ Isolating \ i_{New}: \\ \\ i_{New}=\frac{v}{2R} \therefore i_{New}=\frac{1}{2}\frac{v}{R} \therefore i_{New}=\frac{1}{2}i$

In conclusion, <em>the current will drop to half of its original value.</em>

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A flywheel having constant angular acceleration requires 4.00 ss to rotate through 164 radrad . Its angular velocity at the end

ExtremeBDS [4]

Answer:

$\omega '=-13.5rad/s$

Explanation:

From the question we are told that:

Time $t=4sec$

Angular displacement $\theta= 161 rad$

Final Angular velocity $\omega = 100 rad / s$

Let

Angular acceleration $\alpha$

Generally the equation for Initial Angular velocity $\omega '$ is mathematically given by

$-\omega '^2=2 \alpha \theta -\omega^2$

$\omega '^2= \alpha 328 +11236$

Also,Initial Angular velocity $\omega '$ is mathematically given by

$\omega '=\omega - \alpha t$

Therefore substitution

$-\omega '^2=2 \alpha \theta -\omega^2$

$\omega '=\omega - \alpha t$

$(\omega - \alpha t)^2=2 \alpha \theta -\omega$

$-16\alpha^2+848\alpha+11236= \alpha 328 -11236$

$16\alpha^2-520\alpha=0$

$\alpha=29.875rads/s^2$

Substitution in the 2nd equation for Initial Angular velocity $\omega '$

$\omega '=106-(29.875rads/s^2*4)$

$\omega '=-13.5rad/s$

6 0

3 years ago

Help pls i need this right now

BabaBlast [244]

Answer:

C = - 1.625 i + 6.06 j

Explanation:

Positive angles are measured counterclockwise.

Positive angles are measured counterclockwise. To determine the component on the x axis we use the cosine of the angle while to determine the component on the y axis we use the sine of the angle.

$C_{x}=6.28*cos(105)=-1.625\\C_{y}=6.28*sin(105)=6.06\\$

C = - 1.625 i + 6.06 j

5 0

3 years ago

Jill has a mixture of sand and iron fillings. The mass of the mixture is 250 g. Jill uses a magnet to seperate the two substance

mars1129 [50]

The total mass of the mixture is 250g

And the mass of the sand is 150 g

So...

250 - 150 = Mass of iron fillings

100g = Mass of the iron fillings

6 0

3 years ago

I need help with this pls

noname [10]

Answer:

C = (7 + 8) i + (5 - 1) j adding vectors

C = 15 i + 4 j

theta = arctan (4 / 15) = 14.9 deg

Note that this is the same as adding x and y components

8 0

3 years ago

Calculate the limit of resolution for the oil lens of your microscope. assume an average wavelength of 500 nm

natima [27]

The resolution of a microscope is the distance with the shortest measurement between two different points given a specimen with the premise that it can still be seen clearly or distinguished by the one looking through the microscope. It can be calculate from the ratio of the wavelength of the light and twice the numerical aperture or the refractive index of the lens. Most of the microscopes have a numerical aperture ranging from 1.2 to 1.4. Resolution and the numerical aperture are indirectly proportional so that as the aperture increases the resolution would decrease. We calculate as follows:

<span>Resolution = wavelength / ((2) (numerical aperture))
Resolution = 500 nm / (2 ) ( 1.25) = 200 nm = 0.2 um</span>

3 0

4 years ago