<span>This projectile has been thrown in an oblique movement, so it’s moving in x and in y at the same time. Vy varies due to gravity, and Vx is a constant as there is no gravity in the horizontal direction. In order to calculate Vx, you have to use the angle:
Vx=V*cosa=12m/s*cos(14.2)= 11.6m/s
So now you should use Vx the same way it is used in a uniform linear movement.
d=v*t
dx=vx*t
t=dx/vx=7m/(11.6m/s)=0.603s</span>
Answer:
Here we have some of the requirement of practical fuel are
1. It must contain large amount of stored energy. So that more amount of power output available to run the engines, motors etc.
2. It must occur in abundance in nature or be easy to produce.
3. The fuel must be made up of elements that combine easily with oxygen. Foe example if hydrogen molecules reacts with oxygen. Then the products are at the reaction of lower energy than the reactants, the result is the explosive release of energy and the product of water.
Answer:
S=48.29 m
Explanation:
Given that the height of the hill h = 2.9 m
Coefficient of kinetic friction between his sled and the snow μ = 0.08
Let u be the speed of the skier at the bottom of the hill.
By applying conservation of energy at the top and bottom of the inclined plane we get.
Potential Energy=kinetic Energy
mgh = (1/2) mu²
u² = 2gh
u²=2(9.81)(2.9)
=56.89
u=7.54 m/s
a = - f / m
a = - μ*m*g / m
a = - μg
From equation of motion
v²- u² = 2 -μ g S
v=0 m/s
-(7.54)²=-2(0.06)(9.81)S
S=48.29 m
Explanation:
Net force on the car= mass of the car × acceleration
F=1×10^3×4.5
=4.5×10^3 N
