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Juliette [100K]
3 years ago
8

Find the center and radius of the circle defined by the equation x^2+y^2-7x+3y-4=0

Mathematics
1 answer:
scoray [572]3 years ago
3 0

Answer:

C. center: (7/2, -3/2); radius: sqrt(74)/2

Step-by-step explanation:

x^2 + y^2 - 7x + 3y - 4 = 0

We can put the equation in standard form by completing the square in x and in y.

x^2 - 7x + ___ + y^2 + 3y + ___ = 4 + ___ + ___

x^2 - 7x + (7/2)^2 + y^2 + 3y + (3/2)^2 = 4 + (7/2)^2 + (3/2)^2

(x - 7/2)^2 + (y + 3/2)^2 = 16/4 + 49/4 + 9/4

(x - 7/2)^2 + (y + 3/2)^2 = 74/4

(x - 7/2)^2 + (y + 3/2)^2 = (sqrt(74)/2)^2

Answer: center: (7/2, -3/2); radius: sqrt(74)/2

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Jack and Jill live 126 km apart. They want to leave their homes at the same time,
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Answer:

Both will leave their homes to meet on time at 9 am  

Step-by-step explanation:

Given as, Distance between Jack  and Jill = 126 km

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Time taken by Jack and Jill = T hours

Now , Distance = Speed × Time

So,     x = 18 × T

And  126 - x = 24 × T

Or,    126 - x =  24 × \frac{x}{18}

Or,    126 - x =  x × \frac{4}{3}

Or,    378 - 3x = 4x

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i.e x = \frac{378}{7} = 54 km

And distance travel by Jill = 126 - 54 = 72 km

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∵ Both Jack and Jill will take 3 hours to meet at 12 : 00 pm

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