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weqwewe [10]
3 years ago
5

The zinc within a copper-plated penny will dissolve in hydrochloric acid if the copper coating is filed down in several spots (s

o that the hydrochloric acid can get to the zinc). The reaction between the acid and the zinc is as follows: 2H+(aq)+Zn(s)→H2(g)+Zn2+(aq). When the zinc in a certain penny dissolves, the total volume of gas collected over water at 25 ∘C was 0.953 L at a total pressure of 752 mmHg .
Chemistry
1 answer:
Nonamiya [84]3 years ago
7 0

Answer: 0.0746 grams of hydrogen

Explanation:

To calculate the mass of hydrogen :

(Vapor pressure of water is 23.78 mmHg at 25 ∘C )

2H^+(aq)+Zn(s)\rightarrow H_2(g)+Zn^{2+}(aq)

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

According to the ideal gas equation:

PV=nRT

P = Total Pressure = 752 mm Hg

pressure of hydrogen = Total Pressure - Vapor pressure of water =  (752 -23.78 )mm Hg = 728.22 mm Hg =  0.958 atm   (760mmHg=1atm)

V= Volume of the gas = 0.953 L

T= Temperature of the gas = 25°C = 298 K  

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= ?

n=\frac{PV}{RT}=\frac{0.958\times 0.953}0.0821\times 298}=0.0373moles

Mass of H_2=moles\tims {\text {molar mass}}=0.0373mol\times 22g/mol=0.0746g

Thus 0.0746 grams of hydrogen is collected.

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50 points I need help on this whole work sheet about converting moles
kozerog [31]

Answer:

Explanation:

11)

Answer:

9.08 mol

Given data:

Number of moles of P₂O₅ = ?

Number of moles of O₂ = 22.7 mol

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

                               O₂      :        P₂O₅

                                 5      :          2

                                 22.7  :        2/5×22.7 = 9.08

12)

Answer:

7 mol

Given data:

Number of moles of P₂O₅ = ?

Number of moles of P = 14 mol

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P₂O₅ with P.

                               P        :        P₂O₅

                               4        :          2

                                14      :        2/4×14 = 7

13)

Answer:

76.25 mol

Given data:

Number of moles of P =  61 mol

Number of moles of O₂ react = ?

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P with O₂.

                                  P         :        O₂

                                  4          :          5

                                 61          :        5/4×61 = 76.25

14)

Answer:

1.25 mol

Given data:

Number of moles of P₂O₅ = 0.5 mol

Number of moles of O₂ needed = ?

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

                                P₂O₅         :        O₂

                                  2            :          5

                                0.5          :        5/2×0.5 = 1.25

15)

Answer:

20 mol

Given data:

Number of moles of P₂O₅ = 8 mol

Number of moles of O₂ needed = ?

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

                                P₂O₅       :        O₂

                                  2            :          5

                                  8            :       5/2×8 = 20

16)

Answer:

12 mol

Given data:

Number of moles of silver made = ?

Number of moles of Ag₂O = 6 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles of Ag with Ag₂O .

                       Ag₂O      :       Ag

                           2         :        4

                           6          :        4/2×6 = 12

17)

Answer:

25 mol

Given data:

Number of moles of silver made = ?

Number of moles of O₂ produced = 6.25 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles of Ag with O₂ .

                          O₂             :       Ag

                           1               :        4

                           6.25          :      4×6.25 = 25

18)

Answer:

9.8 mol

Given data:

Number of moles of silver made = ?

Number of moles of O₂ produced = 2.45 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles of Ag with O₂ .

                          O₂             :       Ag

                           1               :        4

                          2.45          :      4×2.45 = 9.8

19)

Answer:

4.4 mol

Given data:

Number of moles of silver oxide required = ?

Number of moles of O₂ produced = 2.2 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles Ag₂O of with O₂ .

                           O₂            :       Ag₂O

                           1               :         2

                          2.2            :        2×2.2  = 4.4

20)

Answer:

1.5 mol

Given data:

Number of moles of silver oxide required = ?

Number of moles of O₂ produced = 0.75 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles Ag₂O of with O₂ .

                           O₂            :         Ag₂O

                           1               :            2

                          0.75            :        2×0.75 = 1.5

8 0
3 years ago
The specific heat of copper metal is 0. 385 J/(g °C). How much energy must be added to a 35. 0-gram sample of copper to change t
Rus_ich [418]

The amount of heat required for changing the temperature of copper has been 606 J. Thus, option B is correct.

Specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The heat required to raise the temperature has been expressed as:

\rm Heat=mass\;\times\;specific\;heat\;\times\;Change\;in\;temperature

<h3>Computation for the heat energy required</h3>

The given specific heat of copper has been \rm 0.385\;J/g^\circ C

The mass of copper has been, \rm 35\;g

The initial temperature of copper has been, \rm 20^\circ C

The final temperature of copper has been, \rm 65^\circ C

The change in temperature has been, \Delta T

\Delta T=\text{Final\;temperature-Initial\;temperature}\\\Delta T =65^\circ \text C-20^\circ \text C\\\Delta T=45^\circ \text C

Substituting the values for the heat required as:

\rm Heat=35\;g\;\times\;0.385\;J/g^\circ C\;\times\;45^\circ C\\Heat=606\;J

The amount of heat required for changing the temperature of copper has been 606 J. Thus, option B is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

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The atomic number of nitrogen is 7. How many protons, neutrons, and electrons make up an atom of Nitrogen-15?
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