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SSSSS [86.1K]
3 years ago
10

I need the definition of metallic bonds I can not find the exact definition. Please help 20 points and Briainest

Chemistry
1 answer:
Kobotan [32]3 years ago
5 0
I believe the answer is A, an attractive force between delocalized electrons and metal cations :)
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PLS HELP! WILL MARK BRAINLIEST!!! 50 PTS
AveGali [126]

Answer:

from the pic:

empirical \: formular :  \:  \: C  _{2}H _{3}O _{2}

since molar mass is 118.084 g/mol;

(C  _{2}H _{3}O _{2}) _{n} = 118.084 \\ C  _{2n}H _{3n}O _{2n} = 118.084 \\(12 \times 2)  _{n} + (1 \times 3) _{n} + (16 \times2 ) _{n} = 118.084 \\ 24_{n} + 3_{n} + 32_{n} = 118.084 \\ 59_{n} = 118.084 \\ n = 2

{ \boxed{ \bf{molecular \: formular :  \: C  _{4}H _{6}O _{4}}}}

It is an aldehyde with structure ( second pic )

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3 years ago
True or False<br> Helium belongs to Noble Metals
Lostsunrise [7]

Answer:

This answer is "True"

6 0
3 years ago
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You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the
Makovka662 [10]

The empirical formula of this compound is Fe_2O_3

<h3>Empirical formula </h3>

To calculate the empirical formula of a compound, the value of moles of each element is needed.

As we have the information of the mass value, we will use the molar mass expression, which corresponds to:

MM_O = 16g/mol\\MM_Fe = 55.8g/mol

                                              MM = \frac{m}{mol}

  • O

                                                   16 = \frac{4.8}{x}

                                                   x = 0.3mol

  • Fe

                                                    55.8=\frac{11.2}{x}\\x = 0.2

As the value of the empirical formula must be an integer, simply multiply the two values ​​by a common factor:

                                                O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2

                                                       Fe_2O_3

So, the empirical formula of this compound is Fe_2O_3.

Learn more about empirical formula: brainly.com/question/1247523

3 0
2 years ago
The ionic equation for MgCl2 and KOH.
saw5 [17]
The reaction of Mg Cl2 and KOH can be described as a double substitution type of reaction. This means the cations of the reactants are exchanged in places when the products are formed. In this case, the balanced reaction is expressed
MgCl2 (s) + 2KOH (aq) = Mhg (OH)2 (aq) + 2KCl (s)
5 0
3 years ago
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PLEASE HELP!?!.!,! What are the products of the combustion of a hydrocarbon?
Tatiana [17]

Answer:

carbon dioxide and water

Explanation:

Example: Combustion of Methane (CH₄(g))

CH₄(g) + 2O₂(g) => CO₂(g) + 2H₂O(g)**

____________________

Note: The combustion of any hydrocarbon produces CO₂ & H₂O. That is,

Ethane (C₂H₆) + O₂ => CO₂(g) + H₂O(g)

Propane (C₃H₈) + O₂ => CO₂(g) + H₂O(g)

Butane (C₄H₁₀) + O₂ => CO₂(g) + H₂O(g)

The issue remaining is to balance the reaction equation. For these type equation balance Carbon 1st, then Hydrogen and finish with Oxygen. Balancing in this order leaves Oxygen which can be balanced using fractions. If problem requires lowest whole number ratios of elements, simply multiply entire equation by 2 to get standard equation*

______________________

*Standard Equation is defined as the smallest whole number ratios of elements. The 'standard equation' is significant in that it is assumed to be at STP conditions; i.e., 0⁰C (=273K) & 1.0 Atmosphere pressure.

  • Ethane (C₂H₆) + 7/2O₂(g) => 2CO₂(g) + 3H₂O(g)

    => 2C₂H₆ + 7O₂(g) => 4CO₂(g) + 6H₂O(g)  <= Standard Form of Rxn

  • Propane (C₃H₈) + 5O₂(g) => 3CO₂(g) + 4H₂O(g) <= Standard Form of Rxn (no need to balance with the '2' multiple)
  • Butane (C₄H₁₀) + 13/2O₂ => 4CO₂(g) + 5H₂O(g)

    => 2C₃H₈ + 13O₂(g) => 4CO₂(g) + 5H₂O(g) <= Standard Form of Rxn

______________________

**Also, note that water, H₂O(g), is listed as a gas. In some cases it will be listed as a liquid, H₂O(l).

3 0
3 years ago
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