Answer:
Step-by-step explanation:
Based on what you have here as the slope we can set the slope formula equal to 34 using the points (0, 8) and (8, c) to solve for c, then use the points (0, 8) and (a, 5) to solve for a.
c first:
and
and
c - 8 = 272 s0
c = 280
For a:
and
and
-34a = 3 so
![a=-\frac{3}{34}](https://tex.z-dn.net/?f=a%3D-%5Cfrac%7B3%7D%7B34%7D)
That seems a little weird, but when you plug those points into the slope formula to solve for the slope, it works out the way it should.
B/ 4 oranges for $1.52 I think.
the answer is 7 - 8/x + 1.
Let's recall that I = Prt
so... hmm we're assuming here, it doesn't say there, but this is for 1 year period.
ok... so... let's use two quantities for such interest, say "a" is the Interest for the Principal of 6000, and let's use "b" is the Interest for the Principal of 13000.
![\bf \qquad \textit{Simple Interest Earned}\\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\to& \$6000\\ r=rate\to r\%\to& \frac{r}{100}\\ t=years\to &1 \end{cases} \\\\\\ a=6000\left( \frac{r}{100} \right)1\implies \stackrel{\textit{P=6000}}{a=60r}\\\\ -------------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BSimple%20Interest%20Earned%7D%5C%5C%5C%5C%0AI%20%3D%20Prt%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AI%3D%5Ctextit%7Binterest%20earned%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%246000%5C%5C%0Ar%3Drate%5Cto%20r%5C%25%5Cto%26%20%5Cfrac%7Br%7D%7B100%7D%5C%5C%0At%3Dyears%5Cto%20%261%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0Aa%3D6000%5Cleft%28%20%5Cfrac%7Br%7D%7B100%7D%20%5Cright%291%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BP%3D6000%7D%7D%7Ba%3D60r%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C)
![\bf \qquad \textit{Simple Interest Earned}\\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\to& \$13000\\ r=rate\to (r-1)\%\to &\frac{r-1}{100}\\ t=years\to &1 \end{cases} \\\\\\ b=13000\left( \frac{r-1}{100} \right)1\implies \stackrel{\textit{P=13000}}{b=130(r-1)}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BSimple%20Interest%20Earned%7D%5C%5C%5C%5C%0AI%20%3D%20Prt%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AI%3D%5Ctextit%7Binterest%20earned%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%2413000%5C%5C%0Ar%3Drate%5Cto%20%28r-1%29%5C%25%5Cto%20%26%5Cfrac%7Br-1%7D%7B100%7D%5C%5C%0At%3Dyears%5Cto%20%261%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0Ab%3D13000%5Cleft%28%20%5Cfrac%7Br-1%7D%7B100%7D%20%5Cright%291%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BP%3D13000%7D%7D%7Bb%3D130%28r-1%29%7D)
now, we know that, whatever the interest amount of "a" is, is 220
less than whatever "b" is.
we know what "b" is,
b = 130(r-1), and 220 less than that is just b - 220, or
130(r-1) - 220.