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2 years ago

PLZ HELPPP What number is 70% of 60?

Mathematics

2 answers:

kvasek [131]2 years ago

5 0

Answer:

Step-by-step explanation:

34kurt2 years ago

3 0

Answer:

Step-by-step explanation:

42/60 = 70%

(Hope I helped)

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Precal help if you could could you answer both. Me finishing this helps me graduate.

oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

$z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))$

In this form, you have

$z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))$

The magnitude of the number is given by

$z=a+bi \implies \rho = \sqrt{a^2+b^2}$

So, we have

$z=-1+\sqrt{3}i \implies \rho = \sqrt{1+3}=2$

As for the angle, we have

$z=a+bi \implies \theta = \text{atan2}\dfrac{b}{a}$

So, we have

$z=-1+\sqrt{3}i \implies \theta = \text{atan2}\left(\dfrac{-\sqrt{3}}{-1}\right) = -\dfrac{2\pi}{3}$

Finally,

$z=-1-\sqrt{3}i = 2\left(\cos\left( -\dfrac{2\pi}{3}\right) + i\sin\left( -\dfrac{2\pi}{3}\right)\right) \implies z^6 = 2^6\left(\cos\left( -4\pi\right) + i\sin\left(-4\pi\right)\right) = 64$

Exercise 2:

You simply have to compute the trigonometric function:

$\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2},\quad \sin\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}$

So, we have

$z = \sqrt{2}\left(\dfrac{\sqrt{2}}{2} - i\dfrac{\sqrt{2}}{2}\right) = 1-i$

7 0

2 years ago

Solve for c.

ANTONII [103]

Answer:

c = 75

Hope this helps!

Step-by-step explanation:

c + 38 = 113

c + 38 - 38 = 113 - 38

c = 113 - 38

c = 75

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Katarina [22]

Answer:

Step-by-step explanation:

1, 17, and 20 are very different from the average numbers in this list.

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2 years ago

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Nikolay [14]

Omg this looks hard

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Fill in the blanks below in order to justify whether or not the mapping shown

Digiron [165]

Basically, it is not a function because 1 domain (in this case, 5) can not be connected to two different ranges(1 and -2). Each domain must only connect to one range.

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2 years ago