Answer:
33+12t−21t^2
Step-by-step explanation:
(2t-7)²-(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².
4t^2−28t+49−(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².
4t^2−28t+49−(25t^2−40t+16)
To find the opposite of 25t^2
−40t+16, find the opposite of each term.
4t^2−28t+49−25t^2−40t+16
Combine 4t^2 and −25t^2 to get −21t^2.
−21t^2−28t+49+40t−16
Combine −28t and 40t to get 12t.
−21t^2+12t+49−16
Subtract 16 from 49 to get 33.
−21t^2+12t+33
Swap terms to the left side.
33+12t−21t^2
I hope this helped!
Answer:
The correct answer is: Option D) 5
Step-by-step explanation:
Given equation is:
In order to find that which values of x makes the equation true, we have to put each value of x in the equation. When both sides of equations will be equal, that value of x will be true for the equation.
Putting x = 2
Putting x = 3
Putting x=4
Putting x = 5
The equation is true for x = 5
Hence,
The correct answer is: Option D) 5
Answer:
Use the graph to write a linear function that relates y to x. The points lie on a line. Find the slope and y-intercept of the line. Because the line crosses the y-axis at (0, −3), the y-intercept is −3.w
Step-by-step explanation:
There are three standard forms for linear functions y = f(x):
f(x) = mx + b (The "slope-intercept" form),
y - yo = m(x - x0) or, equivalently, f(x) = y0 + m(x - x0) (The "point-slope" or "Taylor" form), and.
Ax + By = C (The "general form") which defines y implicitly as a function of x as long as B 0.
The distance formula is: d = sqrt( (x2 - x1)2 + (y2 - y1)2 )
For this problem, let (-5, -4) be the "first" point, so x1 = -5 and y2 = -4
and let (-6, 4) be the "second" point, so x2 = -6 and y2 = 4.
Then: d = sqrt( (-6 - -5)2 + (4 - -4)2 ) = sqrt( (-1)2 + (8)2 ) = sqrt( 1 + 64 ) = sqrt( 65)
The distance formula is just the Pythagorean Theorem applied to an x-y graph.
You would get the same final answer if you let (-5, -4) be the second point and (-6, 4) be the first point.
From point A, draw a line segment at an angle to the given line, and about the same length. The exact length is not important. Set the compasses on A, and set its width to a bit less than one fifth of the length of the new line. Step the compasses along the line, marking off 5 arcs. Label the last one C. With the compasses' width set to CB, draw an arc from A just below it. With the compasses' width set to AC, draw an arc from B crossing the one drawn in step 4. This intersection is point D. Draw a line from D to B. Using the same compasses' width as used to step along AC, step the compasses from D along DB making 4 new arcs across the line. Draw lines between the corresponding points along AC and DB. Done. The lines divide the given line segment AB in to 5 congruent parts.
