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Anastaziya [24]
4 years ago
5

You are using a bucket of water in a science experiment. You conclude that water is a liquid because...?

Physics
1 answer:
stellarik [79]4 years ago
8 0
"A It takes the shape of the container" is the best answer, although liquids also move easily from source to source. Gasses also do this, but to a slightly lesser extent.
You might be interested in
If a plane is inclined at an angle 5o with the horizontal and a cylindrical metal is allowed to roll between two fixed height 92
marysya [2.9K]

Answer:

0.61 second.

Explanation:

So, from the question we are given the following useful parameters or data or information that is going to assist us in solving this question and they are;

(1). Inclination of plane, θ = 50°.

(2). ''The horizontal and a cylindrical metal is allowed to roll between two fixed height 92cm apart on the plane" that is height = 0.92 m(92cm).

(3). The "acceleration of the cylinder to be 2/3 × g Sin (theta) and g = Acceleration due to gravity = 9.8m/s^2

Soz let us delve right into the solution to the question above. We will be making use of the mathematical representation or Equation below;

s = (1/2) a × t².

Where s = height, a = acceleration due to gravity and t = time.

0.92 = (9.8 × sin 50°/ 3) × t².

t² = 0.37

t = √ 0.37.

t =0.61 seconds.

8 0
4 years ago
A projectile is launched with an initial velocity 60m/s at an angle 60° to the vertical. What the magnitude of it's displacement
emmasim [6.3K]

Answer:

the magnitude of the displacement after 5s is 137.31 m.

Explanation:

Given;

initial velocity of the projectile, u = 60 m/s

angle of projection, θ = 60°

time of motion, t = 5s

the vertical component of the velocity, u_y= u\ sin \theta = 60sin(60^0)

The magnitude of the displacement after 5s is calculated as;

h = u_yt -\frac{1}{2} gt^2\\\\h = 60sin (60^0)\times 5 - \frac{1}{2} (9.8)(5)^2\\\\h = 259.81-122.5\\\\h = 137.31 \ m

Therefore, the magnitude of the displacement after 5s is 137.31 m.

3 0
3 years ago
A 90.0-kg man runs at a constant speed of 11.5 m/s. what is his kinetic energy?
harina [27]

The kinetic energy possessed by the man is 517.5 Joules.

<u>Given the following data:</u>

  • Mass = 90.0 kg
  • Velocity = 11.5 m/s.

To find the kinetic energy of the man:

Kinetic energy is an energy that is possessed by a physical object or body due to its motion.

Mathematically, kinetic energy is calculated by using the formula;

K.E = \frac{1}{2} MV^2

<u>Where:</u>

  • K.E is the kinetic energy.
  • M is the mass of an object.
  • V is the velocity of an object.

Substituting the given values, we have;

K.E = \frac{1}{2} × 90 × 11.5

K.E = 45 × 11.5

<em>Kinetic energy = 517.5 Joules.</em>

Therefore, the kinetic energy possessed by the man is 517.5 Joules.

Read more: brainly.com/question/23153766

8 0
3 years ago
Pls help 100 points plssssssss
natima [27]

Answer:

d

Explanation:

8 0
2 years ago
Read 2 more answers
On land, coal is transported primarily by train. A typical large coal train may be about 1.5 km long and may consist of 120 cars
WINSTONCH [101]

Answer:

equivalent power = 6.60 × 10^{12} W

Explanation:

given data

coal train length = 1.5 km = 1500 m

contain = 120 cars

holding= 110 tonnes of coal each

train traveling speed = 100 km/h = 27.78 m/s

to find out

equivalent power in watts

solution

we take here energy produce by coal is 27 ×  10^{6} J/kg

and here total coal = 120 × 110  × 10³ kg

sop here energy produce by total coal is

energy produce by total coal = 27 ×  10^{6} × 120 × 110  × 10³  

and time required to cross that distance is

time = \frac{distance}{speed}    

time = \frac{1500}{27.78}  

time = 53.99 sec

so here equivalent power will be

equivalent power = \frac{energy}{time}  

equivalent power = \frac{27*10^6*120*110*10^3}{53.99}  

equivalent power = 6.60 × 10^{12} W

6 0
3 years ago
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