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PSYCHO15rus [73]
4 years ago
10

A 100-year flood is the flooding elevation that has a one percent chance of happening each year. Why is the name misleading

Physics
1 answer:
fenix001 [56]4 years ago
5 0
One percent annual chance of flooding does not mean it will happen with absolute certainty once every 100 years. Just that the expected value of a flood in 100 years is one.

As an example, heads has a 50% chance of happening every coin flip. With 2 coin flips, the expected value is one. However, it would be a misnomer to call "heads" a 2-flip outcome.
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The two lenses in a microscope are separated by 19.5 cm, and the focal length of the eyepiece lens is 2.75 cm.
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Answer:

Explanation:

a )  If the image of this object is viewed with the eyepiece adjusted for minimum eyestrain (image at the far point of the eye) , the image from object lens must have been formed at the focus of eye lens . So the objective image must have been formed at 19.5 - 2.75 = 16.75 cm from the object lens.

b ) Let the object distance be u

For object lens

v = 16.75 cm , f = .35 cm

1/v - 1/u = 1/f

1/16.75  - 1/u = 1/ .35

.0597 - 1/u = 2.857

1/u = - 2.7973

u = .3575 cm

c ) Angular magnification

= \frac{v_o}{u_o} \times\frac{D}{f_e}

v₀ and u₀ are image and object distance for object lens , D = 25 cm and f_e is focal length of eye lens

= (16.75 / .3575) x( 25 / 2.75)

= 46.85 x 9.09

= 426

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3 years ago
Calculate the first and second velocities of the car with four washers attached to the pulley, using the formulas v1 = 0. 25 m /
castortr0y [4]

The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Given data:

The value of the first distance is, d1 = 0.25 m.

The value of the second distance is, d2 = 0.50 m.

The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,

v = d/t

Here,

d is the distance covered.

t is the average time taken to cover the distance.

Then the first velocity of the car at 0.25 m is,

v1 = d1/t1

v1 = 0.25 / t1

here, t1 is the average time for first distance.

And the second velocity of the car with four washers at the 0. 50 m mark is,

v2 = d2/t2

v2 = 0.50 /t2

here, t2 is the average time for the second distance.

Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Learn more about the velocity here:

brainly.com/question/862972

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