Since Fg=(Gm1m2)/r^2, if the masses are halted the gravitational force will be effected as well. In this case, the gravitational force would be lessened as well.
Answer:
<h2>I hope it's helpful for you</h2>
Answer:
q=3.5*10^-4
Explanation:
<u>concept:</u>
The force acting on both charges is given by the coulomb law:
F=kq1q2/r^2
the centripetal force is given by:
Fc=mv^2/r
The kinetic energy is given by:
KE=1/2mv^2
<u>The tension force:</u>
<u><em>when the plane is uncharged </em></u>
T=mv^2/r
T=2(K.E)/r
T=2(50 J)/r
T=100/r
<u><em>when the plane is charged </em></u>
T+k*|q|^2/r^2=2(K.E)charged/r
100/r+k*|q|^2/r^2=2(53.5 J)/r
q=√(2r[53.5 J-50 J]/k) √= square root on whole
q=√2(2)(53.5 J-50 J)/8.99*10^9
q=3.5*10^-4
<span>C.) A metalloid is used because it is a semiconductor and can become more conductive when more light shines on it.
Nonmetals do not conduct energy any way and you want the metalloid to be conductive so it can provide you with energy.
</span><span>C.) intermediate conductivity and a high melting point
</span>It conducts electricity fairly well.
Hope this helps.
Okay so static friction is when the atoms lock themselves into place, which makes it 'hard' to push until you exceed its static force.
You can calculate the Fs by finding your normal force and multiplying it by your static friction force.
N = mg = (9.8)(42) = 411.6 N
Fs = NKs = (411.6)(0.75) = 308.7
a) the maximum force of static friction between her socks and the floor is 308.7 N
b) If you push Mazie with a force of 350 she will slide. She will accelerate if you keep pushing her with the constant force, but if you push her and let go the kinetic friction will eventually bring her to a stop.
c) So this is an interesting question, she's going at a speed of 0.6 m/s. Kinetic friction is pushing her back so theres a negative force which is the force of kinetic friction right. So its NKf = (411.6)(0.62) = 255.192.