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vivado [14]
3 years ago
11

PLS, NO SPAM!!

Physics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer:

The key benefits to this is the athlete thinks and reflects for themselves which is a vital part of the Learning Styles Model. This technique is most useful for more experienced athletes who like to have involvement and their own opinions about their performance.

Explanation:

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Which of the following describes the time over which a periodic wave repeats?
sineoko [7]

Answer:

b

Explanation:

4 0
4 years ago
Cuales son la energias
strojnjashka [21]

Answer:

I know the answer but cannot concert it to Spanish sorry

Explanation:

In physics, energy is the quantitative property that must be transferred to an object in order to perform work on, or to heat, the object. Energy is a conserved quantity; the law of conservation of energy states that energy can be converted in form, but not created or destroyed.

6 0
3 years ago
Read 2 more answers
A car of mass 1200 kg, moving with a speed of 72 mph on a highway,
Keith_Richards [23]

momentum(p) = mass(m) x velocity(v)

KE = kinetic energy = 1/2 mv²

a.

the ratio of the momentum of the SUV to that of the car

\tt \dfrac{mv}{1.5m\dfrac{2}{3}v }=1:1

b.  the ratio of the KE of the SUV to that of the car

\tt \dfrac{1/2\times mv^2}{1/2\times 1.5m\times (\dfrac{2}{3}v )^2}=\dfrac{mv^2}{1.5m\dfrac{4}{6}v^2 }=1:1

8 0
2 years ago
How many neutrons does element X have if its atomic number is 43 and its mass number is 164?
Drupady [299]
Hello, 
The mass number is protons+neutrons=mass number. In this case, we have protons+nuetron=164.The atomic number is simply the number of protons so we have 43+neutrons=164. Subtracting 43 from both sides we get nuetrons=121. Hope this helps!
6 0
3 years ago
Read 2 more answers
You have a 2m long wire which you will make into a thin coil with N loops to generate a magnetic field of 3mT when the current i
Anni [7]

Answer:

<em>radius of the loop =  7.9 mm</em>

<em>number of turns N ≅ 399 turns</em>

Explanation:

length of wire L= 2 m

field strength B = 3 mT = 0.003 T

current I = 12 A

recall that field strength B = μnI

where n is the turn per unit length

vacuum permeability μ  = 4\pi *10^{-7}  T-m/A = 1.256 x 10^-6 T-m/A

imputing values, we have

0.003 = 1.256 x 10^−6 x n x 12

0.003 = 1.507 x 10^-5 x n

n = 199.07 turns per unit length

for a length of 2 m,

number of loop N = 2 x 199.07 = 398.14 ≅ <em>399 turns</em>

since  there are approximately 399 turns formed by the 2 m length of wire, it means that each loop is formed by 2/399 = 0.005 m of the wire.

this length is also equal to the circumference of each loop

the circumference of each loop = 2\pi r

0.005 = 2 x 3.142 x r

r = 0.005/6.284 = 7.9*10^{-4} m = 0.0079 m =<em> 7.9 mm</em>

8 0
3 years ago
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