3 years ago

Solve for y. 3(y-3)=6y

Mathematics

1 answer:

Maksim231197 [3]3 years ago

7 0

3(y-3)=6y 3y+6=6y 6=3y 6/3=3y/3 2=y

You might be interested in

Round 823 to the nearest ten

bulgar [2K]

820

bc it is not 825 or higher it stays the same

4 0

3 years ago

Read 2 more answers

11 The net force on a vehicle that is accelerating at a rate of 1.5 m/s² is 2,800 newtons. What is

ololo11 [35]

Answer:

$Mass = 1867kg$

Step-by-step explanation:

Given

$Force = 2800N$

$Acceleration = 1.5m/s^2$

Required

Determine the mass of the vehicle

This question will be answered using Newton's second law

$Force = Mass * Acceleration$

Substitute values for Force and Acceleration

$2800 = Mass * 1.5m/s^2$

Make Mass the subject

$Mass = \frac{2800N}{1.5m/s^2}$

$Mass = 1866.6667kg$

$Mass = 1867kg$ ---- approximated

<em>Hence, the mass of the vehicle is 1867kg</em>

4 0

3 years ago

Solve for t <br> 1/2t + 6 = -7

zhuklara [117]

1/2t+6=-7
1/2t=-13
t=-26

7 0

3 years ago

Read 2 more answers

6x = 458.40 what is the value of x

professor190 [17]

the answer for x is 76.4. the way to find it is by dividing 458.4 by 6 to find x s value.

6 0

3 years ago

Read 2 more answers

I NEED SOME HELP PLEASE

slega [8]

Exact answer is 90pi and volume is 283

8 0

3 years ago