2 years ago

I NEED HELP ASAP (8th grade problem)

Mathematics

1 answer:

DerKrebs [107]2 years ago

3 0

Y r u cheating ima snitch on u

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26. Julie says that sin A/cos A = tan A and sin B / cos B = tan B. Use the triangle shown to prove

PSYCHO15rus [73]

Julie is correct because:

$\frac{\sin A}{\tan A}=\frac{a/c}{b/c}=a/b=\tan A \\ \\ \frac{\sin B}{\cos B}=\frac{b/c}{a/c}=b/a =\tan B$

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1 year ago

HURRY PLEASE!! find the lcm of 3x^2-6x-24 and 9x^2-36

Mrac [35]

Answer:

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Step-by-step explanation:

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3 years ago

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On monday 254 students went on a trip to the zoo all 5 buses were filled 9 students had to travel in cars how many students were

Nady [450]

254-9=245 then you do 245/5 which is equal to 49.

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3 years ago

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Name two corresponding angles to <1?

masya89 [10]

C
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3 years ago

Look at picture. Does anybody know the answer I’m lost?

masha68 [24]

Let $x,y$ be the dimensions of the rectangle. We know the equations for both area and perimeter:

$A=xy=36$

$P=2(x+y)=36 \iff x+y=18$

So, we have the following system:

$\begin{cases}xy=36\\x+y=18\end{cases}$

From the second equation, we can deduce

$y=18-x$

Plug this in the first equation to get

$xy=x(18-x)=-x^2+18=36$

Refactor as

$x^2-18x+36=0$

And solve with the usual quadratic formula to get

$x=9\pm3\sqrt{5}$

Both solutions are feasible, because they're both positive.

If we chose the positive solution, we have

$x=9+3\sqrt{5} \implies y=18-x=18-9-3\sqrt{5}=9-3\sqrt{5}$

If we choose the negative solution, we have

$x=9-3\sqrt{5} \implies y=18-x=18-9+3\sqrt{5}=9+3\sqrt{5}$

So, we're just swapping the role of $x$ and $y$ . The two dimensions of the rectangle are $9+3\sqrt{5}$ and $9-3\sqrt{5}$

6 0

2 years ago