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cluponka [151]
4 years ago
7

The pyramid shown has a square base that is 24 inches on each side. The slant height is 20 inches. What is the surface area of t

he pyramid?
Mathematics
1 answer:
wlad13 [49]4 years ago
3 0
About 1695.54 is the answer. 
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Pls help n hurry i will give brainliest
AlekseyPX

Answer: A) and B)

Step-by-step explanation:

So for the first one, a closed circle means that it includes the point and the graph proceeds in the positive direction. So it will be whatever number it starts on in the x axis is less than or equal to x.

The second one you find the distance it moves each second.

You do this by distance over time d/t. Then you divide the 408 by that number.

So 264cm / 11 seconds = 24 cm/sec

Then 408cm/ 24cm per sec = 17s

8 0
4 years ago
Plz help and show work and will make brainliest if right :)
likoan [24]

2/3 x = y-1 is a linear function

3 0
4 years ago
Limit of x^2-81/x+9<br> As x goes toward -9
Semmy [17]
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




7 0
3 years ago
Find the cost of tiling a rectangular plot of land 300 m long and 150 m wide at the rate of $6 per square m.
SVETLANKA909090 [29]

Answer:

$270,000

Step-by-step explanation:

First, find the area of the plot using the formula A = lw

A = lw

A = (300)(150)

A = 45,000

Then, multiply this by 6 to find the total cost:

45,000(6)

= 270,000

So, the cost to tile the plot is $270,000

7 0
3 years ago
Read 2 more answers
What postulate can be used to prove the triangles are congruent?
Komok [63]
The HL Postulate

You know that the two hypotenuses are congruent and that the two triangles each contain a shared segment in the middle (so by the reflexive property they are congruent). You have two congruent hypotenuses and two congruent legs, so you can conclude congruency by HL.

If you found this helpful, please make this the brainliest answer! :)


3 0
3 years ago
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