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3 years ago

Determine the poles of the magnet. Look at the three compass readings that are on top of the magnet. Label the

Physics

2 answers:

melisa1 [442]3 years ago

6 0

Answer:

the red pointer on the magnet ( grey region) : points towards north

red pointer outside the magnet ( white region) is pointing towards south

Explanation:

please see the attached image

Ilya [14]3 years ago

5 0

Answer:

ALL WILL ATTRACT EACH OTHER ..

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A tennis player practices against a wall, hitting a 0.1 kg ball towards the

pantera1 [17]

Answer: 80 Newton

Explanation:

Initial velocity of ball = +20 m/s.

Final velocity of ball = -20 m/s

Mass of ball = 0.1kg

Time taken = 0.05 seconds

Average force = (Change in momentum of moving ball / Time taken)

Since, change in momentum = Mass (final velocity - initial velocity)

Change in momentum =0.1 x (-20 - (+20))

= 0.1 x (-20-20)

= 0.1 x (-40)

= -4.0 kgm/s

Then, put -4.0 kgm/s in the equation of force when Average Force = (Change in momentum / Time taken)

= (-4.0kgm/s / 0.05 seconds)

= 80Newton (note that the negative sign does not reflect on the magnitude of force)

Thus, the average force exerted on the ball is 80N

3 0

3 years ago

What is free nitrogen

Alenkasestr [34]

Answer:

It is simply molecular nitrogen (N2). Nitrogen, in its molecular form, consists of two nitrogen atoms bound together with a tripple bond

Explanation:

4 0

3 years ago

Read 2 more answers

During a game of tug-of-war, one team exerts a force of 3,500 N to the left. The other team exerts a force of 3,800 N to the rig

Lunna [17]

The answer is b hope this helps
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6 0

3 years ago

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Materials with a density__water will float in water

andreyandreev [35.5K]

materials with a density less than water will float

6 0

4 years ago

Read 2 more answers

A truck is hauling a 300-kg log out of a ditch using a winch attached to the back of the truck. Knowing the winch applies a cons

Pie

Answer:

0.128 s

Explanation:

We have to start by calculating the net force acting on the log. We have two forces:

- The constant pulling force, forward, of F = 2500 N

- The frictional force, backward

The frictional force is given by

$F_f = \mu mg$

where

$\mu=0.45$ is the coefficient of friction

m = 300 kg is the mass of the log

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting,

$F_f = (0.45)(300)(9.8)=1323 N$

So the net force acting on the log is

$F=2500 - 1323=1177 N$

Now, we can find the acceleration of the log by using Newton's second law

$F=ma$

where a is the acceleration. Re-arranging for a,

$a=\frac{F}{m}=\frac{1177}{300}=3.92 m/s^2$

And finally we can find the time it takes for the log to reach a speed of

v = 0.5 m/s

by using the suvat equation:

$v=u+at$

where u = 0 is the initial speed and t the time. Solving for t,

$t=\frac{v}{a}=\frac{0.5}{3.92}=0.128 s$

5 0

4 years ago