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Dmitry_Shevchenko [17]
3 years ago
6

Determine the poles of the magnet. Look at the three compass readings that are on top of the magnet. Label the

Physics
2 answers:
melisa1 [442]3 years ago
6 0

Answer:

the red pointer on the magnet ( grey region) : points towards north

red pointer outside the magnet ( white region) is pointing towards south

Explanation:

please see the attached image

Ilya [14]3 years ago
5 0

Answer:

ALL WILL ATTRACT EACH OTHER ..

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Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.20×10^6 N, one at an angle 14.0∘ west of north,
laila [671]

Answer:

1.45544 J

Explanation:

See attachment

5 0
3 years ago
A pipe is horizontal and carries oil that has a viscosity of 0.14 Pa s. The volume flow rate of the oil is 5.3 × 10-5 m3/s. The
Liula [17]

Answer:

Explanation:

Given

\mu =0.14 Pa.s

Volume Flow rate Q=5.3\times 10^{-5} m^3/s

Length L=37 m

radius r=0.58 cm

D=1.16 cm

According to Hagen-Poiseuille Equation

difference in Pressure is given

\Delta P=\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}-P_{out}=\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}=P_{out}+\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}=1.01325\times 10^5+\frac{128\times 0.14\times 37\times 5.3\times 10^{-5}}{\pi\cdot 1.16^4\times 10^{-8}}

P_{in}=1.01325\times 10^5+6.17\times 10^5

P_{in}=7.19\times 10^5

3 0
3 years ago
One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large
Eva8 [605]

Answer:

6666.67 Newtons

Explanation:

The formula F=ma (force is equal to mass multiplied by acceleration) can be used to calculate the answer to this question.

In this case:

  • mass= 0.1mg= 1*10^-7 kg
  • velocity= 4.00*10^3 m/s
  • time= 6.00*10^-8 s

Using velocity and time, acceleration can be calculated as:

  • a= 6.667*10^10 m/s²

Substituting these values into the formula F=ma, the answer is:

  • F= (1*10^-7)kg * (6.667*10^10) m/s²
  • F= 6666.67 Newtons of force
5 0
3 years ago
Each plate of an air-filled parallel-plate capacitor has an area of 45.0 cm2, and the separation of the plates is 0.080 mm. A ba
maw [93]

Answer:

Option (e)

Explanation:

A = 45 cm^2 = 0.0045 m^2, d = 0.080 mm = 0.080 x 10^-3 m,

Energy density = 100 J/m

Let Q be the charge on the plates.

Energy density = 1/2 x ε0 x E^2

100 = 0.5 x 8.854 x 10^-12 x E^2

E = 4.75 x 10^6 V/m

V = E x d

V = 4.75 x 10^6 x 0.080 x 10^-3 = 380.22 V

C = ε0 A / d

C = 8.854 x 10^-12 x 45 x 10^-4 / (0.080 x 10^-3) = 4.98 x 10^-10 F

Q = C x V = 4.98 x 10^-10 x 380.22 = 1.9 x 10^-7 C

Q =  190 nC

3 0
3 years ago
40 Points!!!!!!!!!!!!!
Firlakuza [10]
The answer is A for sure
3 0
3 years ago
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