At t=10 ~\text{s}t=10 s, a particle is moving from left to right with a speed of 5.0 ~\text{m/s}5.0 m/s. At t=20 ~\text{s}t=20 s
1 answer:
Answer:
to the left.
Explanation:
We can use the equation where v is the velocity at time t and
the velocity at
. Since we want the acceleration we write this equation as:
Considering the <em>direction to the right as the positive one</em>, we have at
, and
at
, so we substitute:
Where the minus sign indicates it is directed to the left.
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Answer:
a) 9.72 mm
b) 4.86 mm
Explanation:
wave length of light λ is 580 nm = 580 \times 10⁻⁹ m
Width of slit d = 0.215\times 10⁻³ m
Distance of screen D = 1.8 m.
Width of one fringe =
Putting the values we get fringe width
=
=4.86 mm.
a) Width of central maxima = 2 times width of one fringe
= 2 times 4.86
=9.72 mm
b) width of each fringe except central fringe is same , no matter what the order is.Only brightness changes .
So width of either of the two first order bright fringe will be same and it will be
= 4.86 mm.
Answer:
Magnetic field, B = 0.042 T
Explanation:
It is given that,
Speed of charged particle,
Angle between velocity and the magnetic field,
Charge,
Magnetic force, F = 0.002 N
The magnetic force is given by :
B is the magnetic field
B = 0.042 T
So, the strength of the magnetic field is 0.042 Tesla. Hence, this is the required solution.
Answer:
ms⁻¹
Explanation:
= diameter of merry-go-round = 4 m
= radius of merry-go-round =
=
= 2 m
= moment of inertia = 500 kgm²
= angular velocity of merry-go-round before ryan jumps = 2.0 rad/s
= angular velocity of merry-go-round after ryan jumps = 0 rad/s
= velocity of ryan before jumping onto the merry-go-round
= mass of ryan = 70 kg
Using conservation of angular momentum
ms⁻¹