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2 years ago

When you run your average step length is 42 inches. How many steps would you have to take to run 1 mile 5(,280 feet)?

Mathematics

1 answer:

Katarina [22]2 years ago

3 0

Answer:

1 508.57143 steps

Step-by-step explanation:

divide 5,280 feet by 42 inches to get 1 508.57143 steps.

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Solution to 3x+5y=-20

zloy xaker [14]

3x+5y=-20

5y=-20divide

the answer is x=-4

3x=-20 divide

the answer is y=-20

3 0

2 years ago

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Find all two-digit numbers with the following property: difference of that number and the number with its reversed digits is 36.

kirza4 [7]

$10x+y-(10y+x)=36\\
10x+y-10y-x=36\\
9x-9y=36\\
x-y=4\\\\
x,y\in\{1,2,3,4,5,6,7,8,9\}\\
\Downarrow\\
x=5,y=1\\
x=6,y=2\\
x=7,y=3\\
x=8,y=4\\
x=9,y=5


$

There are 5 such numbers - 51,62,73,84,95

6 0

2 years ago

1.) Find the value of the discriminant and the the number of real solutions of

ruslelena [56]

Hi there!

When we have an equation standard form...
$a {x}^{2} + bx + c = 0$
...the formula of the discriminant is
D = b^2 - 4ac

When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions

1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0

Plug in the values from the equation into the formula of the discriminant

$( - 8) {}^{2} - 4 \times 1 \times 7 = 64 - 28 = 36$

D > 0 and therefore we have two real solutions.

2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0

Again, plug in the values from the equation into the formula of the discriminant.

${4}^{2} - 4 \times 2 \times 2 = 16 - 16 = 0$

D = 0 and therefore we have one real solution.

~ Hope this helps you.

4 0

2 years ago

Read 2 more answers

A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9, and the sample stand

yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

Step 1: We state the hypothesis and identify the claim

$H_0:\mu=100$ and $H_1:\mu \:>\:100$ (claim)

Step 2: Calculate the test value.

$t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$

$\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263$

Step 3: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

Step 4: We fail to reject the null hypothesis since P-value is greater that the alpha level. (0.134>0.05).

Step 5: There is enough evidence to support the claim that the population mean is greater than 100.

Alternatively: We could also calculate the critical value to obtain +1.685 for $\alpha=0.05$ and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

5 0

3 years ago

What is 0.096 in word for

Luden [163]

0.096 = Ninety-six thousandths

6 0

2 years ago

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