Answer:
The common ratio is 5 and the 5th term is 1250
Step-by-step explanation:
The common ratio is given by
r=U(2)/U (1)
=10/2
=5
The fifth term
U (n)=ar^n-1
U(5)=2(5)^5-1
=2×5^4
=2×625
=1250
Answer:
(0.4958, 0.7422)
Step-by-step explanation:
Let p be the true proportion of water specimens that contain detectable levels of lead. The point estimate for p is
. The estimated standard deviation is given by
. Because we have a large sample, the 90% confidence interval for p is given by
where
is the value that satisfies that above this and under the standard normal density there is an area of 0.05. So, the confidence interval is
, i.e., (0.4958, 0.7422).
Answer:
3x + 2 = 3x - 2
Step-by-step explanation:
Answer:
The biggest factor of 49896 is 24948
9514 1404 393
Answer:
1 < 15 -2a < 7
Step-by-step explanation:
There are a couple of ways you can do this.
1) Put the minimum and maximum values of a into the expression to see what its corresponding values are:
15-2a for a=4:
15-2(4) = 7
15-2a for a=7:
15-2(7) = 1
Then ...
1 < 15-2a < 7
__
2) Solve for a in terms of the value of 15-2a, then impose the limits on a.
x = 15 -2a
2a = 15 -x
a = (15 -x)/2
Now, impose the given limits:
4 < (15 -x)/2 < 7
8 < 15 -x < 14 . . . multiply by 2
-7 < -x < -1 . . . . . . subtract 15
7 > x > 1 . . . . . . . . multiply by -1
1 < 15-2a < 7 . . . . . use x=15-2a
_____
The vertical extent of the attached graph is the range of possible values of 15-2a. It goes from 1 to 7.