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3 years ago

How does tripling the side lengths of a right triangle affects its area?

Mathematics

1 answer:

Andrej [43]3 years ago

6 0

Let $x,y$ be the lengths of the original legs. The original area is thus

$\dfrac{xy}{2}$

Now, we triple the legs, so we have $(x,y)\mapsto(3x,3y)$

The new area is

$\dfrac{(3x)(3y)}{2} = \dfrac{9xy}{2} = 9\dfrac{xy}{2}$

which is 9 times the original area.

So, if you triple both legs, the area will be nine times as much as the original one.

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(Algebra 1 )please help me I'll give brainliest

riadik2000 [5.3K]

7-3/-3-3

4/-6

this can be simplified to -2/3

(3) = -2/3(3) + b

Solve this

3 = -2 + b

5 = b

The answer is

y = -2/3x + 5

7 0

2 years ago

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream. What is the rate of

nikitadnepr [17]

<h3>Rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr</h3><h3><u>Solution:</u></h3>

Given that,

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream

Therefore,

Upstream distance = 165 km

Upstream time = 3 hours

<h3><u>Find upstream speed:</u></h3>

$speed = \frac{distance}{time}\\\\speed = \frac{165}{3}\\\\speed = 55$

Thus upstream speed is 55 km per hour

Downstream distance = 510 km

Downstream time = 6 hours

<h3><u>Find downstream speed:</u></h3>

$speed = \frac{510}{6}\\\\speed = 85$

Thus downstream speed is 85 km per hour

<em><u>If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then</u></em>

Speed downstream = u + v km/hr

Speed upstream = u - v km/hr

Therefore,

u + v = 85 ----- eqn 1

u - v = 55 ----- eqn 2

Solve both

Add them

u + v + u - v = 85 + 55

2u = 140

u = 70

<em><u>Substitute u = 70 in eqn 1</u></em>

70 + v = 85

v = 85 - 70

v = 15

Thus rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr

3 0

3 years ago

Write the following percents as both fractions and decimals.

Leona [35]

(last part)
25%
27.8%
290%
300%
67%

5 0

3 years ago

Read 2 more answers

The selling price for a classic speedboat is $16,000, which is $500 more than two times its original price. What was the origina

lbvjy [14]

$7,750 is the answer :)

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3 years ago

In Grafton, a rural area in Vermont, the distance (in meters) between telephone poles has a uniform distribution between 40 and

coldgirl [10]

Answer:

a) 60% probability that the distance is environment friendly.

b) The mean of the distances between the telephone poles is 52.5 meters.

c) The standard deviation of the distance between the telephone poles is 7.22 meters.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

Uniform distribution between 40 and 65 meters.

This means that $a = 40, b = 65$

a) Any distance between poles greater than 50 meters is considered to be environment friendly. What is the probability that the distance is environment friendly?

This is $P(X > 50)$

We have that

$P(X \leq 50) + P(X > 50) = 1$

$P(X > 50) = 1 - P(X \leq 50)$

$P(X \leq 50) = \frac{50 - 40}{65 - 40} = 0.4$

$P(X > 50) = 1 - P(X \leq 50) = 1 - 0.4 = 0.6$

60% probability that the distance is environment friendly.

b) Find the mean of the distances between the telephone poles

The mean of the uniform distribution is

$M = \frac{a + b}{2}$

$M = \frac{a + b}{2} = \frac{40 + 65}{2} = 52.5$

c) Find the standard deviation of the distance between the telephone poles.

The standard deviation of the uniform distribution is:

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

$S = \sqrt{\frac{(65-40)^{2}}{12}} = 7.22$

5 0

3 years ago