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svlad2 [7]
3 years ago
12

How does tripling the side lengths of a right triangle affects its area?

Mathematics
1 answer:
Andrej [43]3 years ago
6 0

Let x,y be the lengths of the original legs. The original area is thus

\dfrac{xy}{2}

Now, we triple the legs, so we have (x,y)\mapsto(3x,3y)

The new area is

\dfrac{(3x)(3y)}{2} = \dfrac{9xy}{2} = 9\dfrac{xy}{2}

which is 9 times the original area.

So, if you triple both legs, the area will be nine times as much as the original one.

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A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses
Greeley [361]

Answer:

The original duration of the tour  is 18 days.

Step-by-step explanation:

Let

the number of days spent be T

Daily expenses be D

Initially ,

total tour expenses was 360

D \times T=360

D = \frac{360}{T}-------------(1)

If he extends his tour for 4 days, he has to cut down his daily expenses by dollar 3

(D + 4) \cdot(T -3) = 360---------------(2)

Expanding the eqaution(2)

DT-3D + 4T -12 = 360

Substituting the value of D

(\frac{360}{T})T -3( \frac{360}{T}) + 4T -12 = 360

(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 360 + 12

(\frac{360}{T})T -3( \frac{360}{T}) + 4T= 372

360 - ( \frac{1080}{T}) + 4T= 372

( \frac{1080}{T}) + 4T= 372 - 360

( \frac{1080}{T}) + 4T= 12

1080 + 4T^2= 12T

Solving the quadratic equation we get

T = 18  and T = -15

T is the number of gays and it cannot be negative , hence T is 18

Substituting in equation (1) we get

D = \frac{360}{18}

D =  20

4 0
3 years ago
Find the perimeter of a square that is 3 3/4 inches on a side.
Dahasolnce [82]

perimeter would be s x 4

 so 3 3/4 x 4 = 15

 B is the correct answer

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Pani-rosa [81]

Answer:

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Step-by-step explanation:


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Step-by-step explanation:

When x = 5, f(x) = -8.

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