Florida state university has 14 statistics classes scheduled for its summer 2013 term. one class has space available for 30 stud
1 answer:
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Answer:
(a) The correct answer is P (CBM) = 0.79.
(b) The probability of selecting an American female who is not red-green color-blind is 0.996.
(c) The probability that neither are red-green color-blind is 0.9263.
(d) The probability that at least one of them is red-green color-blind is 0.0737.
Step-by-step explanation:
The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.
It is provided that 79% of men and 0.4% of women are colorblind, i.e.
P (CBM) = 0.79
P (CBW) = 0.004
(a)
The probability of selecting an American male who is red-green color-blind is, 0.79.
Thus, the correct answer is P (CBM) = 0.79.
(b)
The probability of the complement of an event is the probability of that event not happening.
Then,
P(not CBW) = 1 - P(CBW)
= 1 - 0.004
= 0.996.
Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.
(c)
The probability the woman is not colorblind is 0.996.
The probability that the man is not color- blind is,
P(not CBM) = 1 - P(CBM)
= 1 - 0.004
= 0.93.
The man and woman are selected independently.
Compute the probability that neither are red-green color-blind as follows:
Thus, the probability that neither are red-green color-blind is 0.9263.
(d)
It is provided that a one man and one woman are selected at random.
The event that “At least one is colorblind” is the complement of part (d) that “Neither is Colorblind.”
Compute the probability that at least one of them is red-green color-blind as follows:
Thus, the probability that at least one of them is red-green color-blind is 0.0737.