Solution (1)
for k=0 / for k=1 / for k=-1
x=0 / x=2π / x=-2π
acc / acc / rej
solution (2)
for k=0 / for k=1 / for k=-1
x=0 / x=2π/3 / x=-2π/3
acc / acc / rej
Note that i'm trying values of K which make the answer belong to our interval;
So our solution which i will represent as a set is;
S € {0,2π/3,2π}
Answer:
8820 ways
Step-by-step explanation:
Given that :
Selecting 4 pairs of pant from 8 available and selecting 5 shirts from 9 available
Using combination :
4 pants from 8 = 8C4
5 shirts from 9 = 9C5
Recall:
nCr = n! / (n-r)! r!
8C4 * 9C5 = [8! /(8-4)!4!] * [9! /(9-5)!5!]
8C4 * 9C5 = (8! /4!4!) * (9! /4!5!)
8C4 * 9C5 = 70 * 126
8C4 * 9C5 = 8820 ways
Answer:
<h3>
aₙ = 8n + 27</h3>
Step-by-step explanation:
