Answer:
The answer to your question is:
a) 2.7 m/s²
b) -3.6 m/s²
Explanation:
Data
mass of the toolbox = 3.2 kg
a = ?
F = 40 N and F = 20 N
g = 9.81 m/s²
Formula
Second law of motion = F = ma
a + g = F / m
a = F/m - g
a) a = 40/3.2 - 9.81
a = 2.69 ≈ 2.7 m/s² positive up
b) a = 20/ 3.2 - 9.81
a = 6.25 - 9.81
= - 3.56 ≈ - 3.6 m/s² negative down
Answer:
20 years Light.
Explanation:
There's no practical explanation just math's.
Answer:
0.312 m/s
Explanation:
Elastic collisions conserve momentum and kinetic energy
The velocity of the center of mass will not change. It continues at
0.00521(443) / 14.80521 = 0.155893... ≈ 0.156 m/s
To conserve kinetic energy we can think of the center of mass (CoM) as an ideal spring returning to each mass that strikes it an identical speed of collision in the opposite direction.
The CoM sees the target approach at - 0.156 and will see it depart at 0.156 m/s
A ground based observer sees the target depart at the velocity of the CoM plus the relative velocity .
v = 0.156 + 0.156 = 0.312 m/s
Answer:
c)X= Vo(t)+1/2at^2
Explanation:
From the question we are told that
initial speed u=10.4
displacement d= 39
time t=3.3s
accelaration a=?
Generally the best equation in solving for Acceleration is given to be
X= Vo(t)+1/2at^2
Mathematically
The volume increases. The molecules of that object gain kinetic energy hence colliding more and creating a bigger gap between each other.
