Acceleration = force / mass = 20 / 2 = 10 m/s^2
Answer:
Intensity of beam 18 feet below the surface is about 0.02%
Explanation:
Using Lambert's law
Let dI / dt = kI, where k is a proportionality constant, I is intensity of incident light and t is thickness of the medium
then dI / I = kdt
taking log,
ln(I) = kt + ln C
I = Ce^kt
t=0=>I=I(0)=>C=I(0)
I = I(0)e^kt
t=3 & I=0.25I(0)=>0.25=e^3k
k = ln(0.25)/3
k = -1.386/3
k = -0.4621
I = I(0)e^(-0.4621t)
I(18) = I(0)e^(-0.4621*18)
I(18) = 0.00024413I(0)
Intensity of beam 18 feet below the surface is about 0.2%
Answer:
10.8 N
Explanation:
The question requires the force between them, hence, we only need the magnitude of the force without considering what direction it's acting.
Parameters given:
Q1 = 15 * 10^(-6) C
Q2 = 10 * 10^(-6) C
The diagram explains better.
The electrostatic force BETWEEN Q1 and Q2 is:
F = (k * Q1 * Q2)/r²
Using Pythagoras theorem:
r² = 0.25² + 0.25² = 0.0625 + 0.0625
r² = 0.125
=> F = [9 * 10^9 * 15 * 10^(-6) * 10 * 10^(-6)]/0.125
F = 1.35/0.125
F = 10.8 N
Answer:
Kg.m/s is the unit for impulse
Explanation:
If i were wrong please correct me.