Answer:
Percent dissociated = 3.92%
Explanation:
The equilibrium of the weak acid, HA, is:
HA ⇄ H⁺ + A⁻
<em>Where Ka = 8x10⁻⁴ is: [H⁺] [A⁻] / [HA]</em>
<em> </em>
As both H⁺ and A⁻ comes from the same equilibrium we can write the concentrations of the species as follows:
[H⁺] = X
[A⁻] = X
[HA] = 0.50M - X
<em>Where X is reaction coordinate</em>
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Replacing:
8x10⁻⁴ = X² / 0.50-X
4x10⁻⁴ - 8x10⁻⁴X - X² = 0
Solving for X:
X = -0.02M. False solution. There is no negative concentrations
X = 0.0196M. Right solution.
Replacing:
[A⁻] = 0.0196M
Percent of the acid that is dissociated is:
[A⁻] / [HA]₀ * 100
<em>[HA]₀ is its initial concentration = 0.50M</em>
0.0196M / 0.50M * 100
<h3>Percent dissociated = 3.92%</h3>
Answer:
Magnetism is the force of attraction on a magnetic substance by a magnet.
Explanation:
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In a chemical reaction equation.. There must be redox reaction taking palce.. So oxidation and reduction reactions will be happening on both sides of the equation.. You can separate the oxidation and reduction equations in halves. . So there will be one half oxidation equation and the other half reduction equation of the reaction.
<span>No, all cars will not have the same amount of force available to them. The majority of a car's force comes from the engine of the vehicle. All engines do not have the same amount of power in that some have larger amounts of force and some have smaller amounts of force. This will result in cars having different amounts of available force.</span>
The mass of magnesium cyanide needed to prepare the solution is 1.57 g
We'll begin by calculating the number of mole of Mg(CN)₂. This can be obtained as follow:
Volume = 275 mL = 275 / 1000 = 0.275 L
Molarity of Mg(CN)₂ = 0.075 M
<h3>Mole of Mg(CN)₂ =? </h3>
Mole = Molarity x Volume
Mole of Mg(CN)₂ = 0.075 × 0.275
Mole of Mg(CN)₂ = 0.020625 mole
- Finally, we shall determine the mass of Mg(CN)₂
Mole of Mg(CN)₂ = 0.020625 mole
Molar mass of Mg(CN)₂ = 24 + 2(12 + 14) = 76 g/mol
<h3>Mass of Mg(CN)₂ =? </h3>
Mass = mole × molar mass
Mass of Mg(CN)₂ = 0.020625 × 76
Mass of Mg(CN)₂ = 1.57 g
Therefore, 1.57 g of Mg(CN)₂ is needed to prepare the solution
Learn more: brainly.com/question/3126258