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3 years ago

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TIMED HELP ASAP

1 answer:

anastassius [24]3 years ago

7 0

Answer:

TIMED HELP ASAP

19.11 g of MgSO₄ is placed into 100.0 mL of water. The water's temperature increases by 6.70°C. Calculate ∆H, in kJ/mol, for the dissolution of MgSO₄. (The specific heat of water is 4.184 J/g･°C and the density of the water is 1.00 g/mL). You can assume that the specific heat of the solution is the same as that of water.

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A beaker is filled to the 500 mL mark with alcohol. What increase in volume (in mL) does the beaker contain when the temperature

Aliun [14]

Answer:

"1.4 mL" is the appropriate solution.

Explanation:

According to the question,

$v_0=500$
$\alpha =1.12\times 10^{-4}$
$\Delta \epsilon = 25$

Now,

Increase in volume will be:

⇒ $\Delta V = \alpha\times v_0\times \Delta \epsilon$

By putting the given values, we get

$=1.12\times 10^{-4}\times 500\times 25$

$=1.12\times 10^{-4}\times 12500$

$=1.4 \ mL$

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3 years ago

The particles in a gas vibrate faster than the particles in a liquid.<br> True<br> False

NISA [10]

Answer:

true

Explanation:

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2 years ago

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A chemical reaction can theoretically produce 1375.5 grams of product , but in actuality 112.9 grams are product . Which is the

zalisa [80]

Answer:

8.20 % → Percent yield reaction

Explanation:

To find the percent yield of reaction we apply this:

(Produced yield / Theoretical yield) . 100 = %

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We replace → (112.9g / 1375.5 g) . 100

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There would be 2 which would be on the oxygen

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Explanation:

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3 years ago