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3 years ago

2. Solve the following system of equations using substitution.

1 answer:

4 0

First, make sure you convert both equations into standard form. Your two equations would be 2x+2y=38 and -x+y=3. Then multiply the bottom by 2. So your new equations would be 2x+2y=38 and -2x+2y=6. The x would cancel out and you would continue solving for y. y would equal 11 and then you would plug it back into an original equation. When you plug and solve for x, you would get x=8. So your answer would be (8,11)

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Plz help been stuck on this for awhile

Kazeer [188]

Answer:

d = $\sqrt{74}$ or 8.60

Step-by-step explanation:

(5, 8) (-2, 3)

Let 5 = $x_{1}$

8 = $y_{1}$

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3 = $y_{2}$

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2 years ago

If the simple interest on $3,000 for 8 years is $1,680, then what is the interest rate?

madam [21]

We need to use the formula for simple interest which is
I= prt
Where I is the amount of money you earned or pay in interest
p is the principal, the amount you deposited or borrowed
r is the interest rate expressed as a decimal
t is time in terms of years

In this problem, I= 1,680
p= 3000
t= 8
'. r is what we are looking for.

Substituting the numbers into the simple interest formula, we get
I=. p r t
1,680=(3000)(r)(8). Multiplying
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