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2 years ago

What property is 74.5*0=0

1 answer:

7 0

74.5 x 0 = 0 belongs to the multiplication property of zero.
Because this property has a rule that any number multiplied by zero, the answer is zero.
It will not matter how big or small the number is, if it will be multiplied by zero, the answer will always be zero.
Another example:
=> 1000 x 0 = 0
=> 1524 x 0 = 0
=> .25 x 0 = 0
Notice, that even decimal numbers multiplied by zero is still zero.

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if there are about 3.346x10^26 molecules of water in a liter of water and the ocean is about 1.26x10^21 liters in volume, how ma

Natalka [10]

Answer: 4.21596 x 10⁴⁷

Step-by-step explanation:

(3.346 x 10²⁶) (1.26 x 10²¹)

= (3.346 x 1.26) x 10²⁶⁺²¹

= 4.21596 x 10⁴⁷

8 0

2 years ago

The length of a rectangle is 5 inches less than 4 times the width. The perimeter is 110 inches. Find the length and the width.

nataly862011 [7]

Answer:

Length = 43 inches
Width = 12 inches

Step-by-step explanation:

Perimeter of a rectangle = 2 * ( L + W)

The length of a rectangle is 5 inches less than 4 times the width.

Assume the width is x. Length is:

4x - 5

Equation is therefore:

2 * (4x - 5 + x) = 110

4x - 5 + x = 110/2

5x - 5 = 55

5x = 55 + 5

x = 60/5

x = 12 inches

If width is 12 inches, then length is:

= 4x - 5

= 4 * 12 -5

= 43 inches

6 0

2 years ago

Identify the coefficient of −24x7y3

Sloan [31]

The coefficient of these two number are -24 and 7. :)

4 0

2 years ago

Read 2 more answers

Sum of 2 numbers is 5 difference of the same 2 numbers is 9

liq [111]

Answer:

5 and 4

Step-by-step explanation:

7 0

3 years ago

A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6

ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

Now, According to question

The population of bacteria after 6 days = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, f = i × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, f = 1000 × $(1+\dfrac{\textrm 15}{100})^{\textrm 6}$

Or, f = 1000 × $(1.15)^{6}$

Or, f = 1000 × 2.31306

∴ f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06 Answer

3 0

3 years ago