Answer:
D. Complex I, Ubiquinone, Complex III, Cytochrome C, Complex IV, Oxygen.
Explanation:
Answer:
C. Disruptive Selection
Explanation:
Disruptive selection occurs when two extremes of continuous variation are favored more than intermediate traits.
The extremes of continuous variation exhibited in this species of snail is the color of their shell which allows them to blend with the background of their habitat.
The shady forest of the habitat makes the dark-shelled individuals to be better hidden from bird predators, while the light-shelled individuals are better hidden in well-lit brushy edge areas. This disruptive coloration exhibited by both individuals makes both individuals of this species of snail less vulnerable to predation.
Both individuals of this species both extremities would naturally survive in this habitat as snails with intermediate extremities would be highly preyed on since there is no area of intermediate brightness in the habitat to make them invisible to predators
The best conclusion about the
life cycle of this plant is the plant is
a gymnosperm, and the sporophyte is its dominant phase. The
correct answer between all the choices given is the second choice or letter B. I
am hoping that this answer has satisfied your query and it will be able to help
you in your endeavor, and if you would like, feel free to ask another question.
Answer:
The t-test
Explanation:
<em>The researcher should use a t-test to compare the two means and check if they are significantly different from each other.</em>
In using the t-test, both null (H0) and alternate (H1) hypothesis are made such that:
Thereafter, the value of t is calculated and compared to its critical value on the table. The formula for calculating the t goes thus:
where, Y1 = mean of population 1, Y2 = mean of population 2, S1 = variance of population 1, S2 = variance of population 2, n1 = number of individuals in population 1 and s2 = number of individuals in population 2.
<em>At the end of the day, if the calculated t value is more than the critical value of t, the H0 is rejected and it shows that the two means are significantly different. Otherwise, the H0 is accepted and this shows that there is not significant difference between the mean of population 1 and that of 2.</em>