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marysya [2.9K]
3 years ago
10

On the track and field team, 3/8 of the members do the hurdles. Of the members who do the hurdles, 4/5 also do the long jump. If

there are 40 members on the track team, how many do both the hurdles and the long jump? Choose your answer from the dropdown menu.
Mathematics
1 answer:
STALIN [3.7K]3 years ago
3 0
The amount of people who do the hurdles:
\frac{3}{8}  \times 40 = 15
From this 15 people, the following amount does long jump:
\frac{4}{5}  \times 15 = 12
So the answer is 12 people.
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18. The sum of 10 times a number and fifteen is added to eleven times the same number.​
sergij07 [2.7K]

Answer:

Sum of 10 times a number and fifteen is added to eleven times the same number is therefore: 10x + 15 + 11x = 21x + 15

Step-by-step explanation:

4 0
3 years ago
Solve the following problems. Be sure to indicate if a solution is to be rejected based on the contextual situation.
aleksklad [387]

Answer:

1. 5/3 cm

2. 10 in

Step-by-step explanation:

1. The length of a rectangle is 4 cm more than 3 times its width.

Let the length be L and the width B

Then,

L = 4 + 3B

If the area of the rectangle is 15 cm2

Area = LB = 15

B(4 +3B) = 15

3B² + 4B - 15 = 0

3B² - 5B + 9B - 15 = 0

B(3B - 5) + 3(3B - 5) = 0

(3B - 5)(B + 3) = 0

3B - 5 =  or B + 3 = 0

B = 5/3 or -3

since B cannot be negative, B = 5/3 cm

2. The ratio of length to width in a rectangle is 2 ∶ 3.

Let the length be L and the width B

Then,

L/B = 2/3

2B = 3L, B = (3/2)L

when the area is 150 in2.

Area = LB = 150

(3/2)L² = 150

L² = 150×2÷3

L² = 100

L = √100

L = ±10

since the length cannot be negative, L = 10 in

4 0
3 years ago
Consider all 5 letter "words" made from the full English alphabet. (a) How many of these words are there total? (b) How many of
VARVARA [1.3K]

Answer:

a) There are 11,881,336 of these words in total.

b) There are 7,893,600 of these words with no repeated letters.

c) 896,376 of these words start with an a or end with a z or both

Step-by-step explanation:

Our words have the following format:

L1 - L2 - L3 - L4 - L5

In which L1 is the first letter, L2 the second letter, etc...

There are 26 letters in the English alphabet.

(a) How many of these words are there total?

Each of L1, L2, L3, L4 and L5 have 26 possible options.

So there are 26^{5} = 11,881,336 of these words total

(b) How many of these words contain no repeated letters?

The first letter can be any of them, so L1 = 26.

At the second letter, the first one cannot be repeated, so L2 = L1 - 1 = 25.

At the third letter, nor the first nor the second one can be repeated, so L3 = L1 - 2 = 24

This logic applies until L5

So we have

26-25-24-23-22

In total there are

26*25*24*23*22 = 7,893,600

of these words with no repeated letters.

(c) How many of these words start with an a or end with a z or both (repeated letters are allowed)?

T = T_{1} + T_{2} + T_{3}

T_{1} is the number of words that start with an a and do not end with z. So we have

1 - 26 - 26 - 26 - 25

The first letter can only be a, and the last one cannot be z. So:

T_{1} = 26^{3}*25 = 439,400

T_{2} is the number of words that start with any letter other than a and end with z. So we have

25 - 26 - 26 - 25 - 1

The first letter can be any of them, other than a, and the last can only be z. So:

T_{2} = 26^{3}*25 = 439,400

T_{3} is the number of words that both start with a and end with z. So:

1 - 26 - 26 - 26 - 1

The first letter can only be a, and the last can only be z. The other three letters could be anything. So:

T_{3} = 26^{3} = 17,576

T = T_{1} + T_{2} + T_{3} = 2*439,400 + 17,576 = 896,376

896,376 of these words start with an a or end with a z or both

4 0
3 years ago
13. I think it is miles
babymother [125]

Answer:

I think it would be miles.

7 0
3 years ago
Giving thanks and brainliest for best answer <3
Papessa [141]
It’s definitely 100% B sorry if I’m late :)
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3 years ago
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