A 2:5 ratio. Because 21 divided by 7 equals 3 and 35 divided by 7 equals 5. And I did it by 7 because thats common factor
<span>Actually the above equation can be solved by following the below steps to fins the value of x
Step1: 3(x-k)/w=4
Step 2: (3x-3k)/w=4
Step 3: (3x-3k)=4w
Step 4: 3x=4w+3k
So hence therefore by following the above steps we can conclude that the value of x is
Step 5: x=(4w+3k)/3</span>
Compare
to
. Then in applying the LCT, we have
![\displaystyle\lim_{n\to\infty}\left|\frac{\frac1{\sqrt{n^2+1}}}{\frac1n}\right|=\lim_{n\to\infty}\frac n{\sqrt{n^2+1}}=1](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bn%5Cto%5Cinfty%7D%5Cleft%7C%5Cfrac%7B%5Cfrac1%7B%5Csqrt%7Bn%5E2%2B1%7D%7D%7D%7B%5Cfrac1n%7D%5Cright%7C%3D%5Clim_%7Bn%5Cto%5Cinfty%7D%5Cfrac%20n%7B%5Csqrt%7Bn%5E2%2B1%7D%7D%3D1)
Because this limit is finite, both
![\displaystyle\sum_{n=1}^\infty\frac1{\sqrt{n^2+1}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csum_%7Bn%3D1%7D%5E%5Cinfty%5Cfrac1%7B%5Csqrt%7Bn%5E2%2B1%7D%7D)
and
![\displaystyle\sum_{n=1}^\infty\frac1n](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csum_%7Bn%3D1%7D%5E%5Cinfty%5Cfrac1n)
behave the same way. The second series diverges, so
![\displaystyle\sum_{n=0}^\infty\frac1{\sqrt{n^2+1}}=1+\sum_{n=1}^\infty\frac1n](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csum_%7Bn%3D0%7D%5E%5Cinfty%5Cfrac1%7B%5Csqrt%7Bn%5E2%2B1%7D%7D%3D1%2B%5Csum_%7Bn%3D1%7D%5E%5Cinfty%5Cfrac1n)
is divergent.
It could tell you that your amount sold is going up steadily per unit of time
If you want to solve for y then
<span>3xy+y=15
y (3x+1) = 15
y = 15/(3x+1)
</span>