Answer:
(A) Distance will be equal to 1.75 km
(B) Displacement will be equal to 1.114 km
Explanation:
We have given circumference of the circular track = 3.5 km
Circumference is given by 
r = 0.557 km
(a) It is given that car travels from southernmost point to the northernmost point.
For this car have to travel the distance equal to semi perimeter of the circular track
So distance will be equal to 
(b) If car go along the diameter of the circular track then it will also go from southernmost point to the northernmost point. and it will be equal to diameter of the track
So displacement will be equal to d = 2×0.557 = 1.114 m
Answer:
<h3>b.fission. </h3>
Explanation:
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Answer:
False you dont repaint your hamster.
Explanation:
LOL
When I went through with the math, the answer I came upon was:
<span>6.67 X 10^14 </span>
<span>Here is how I did it: First of all we need to know the equation. </span>
<span>c=nu X lamda </span>
<span>(speed of light) = (frequency)(wavelength) </span>
<span>(3.0 X 10^8 m/s) = (frequency)(450nm) </span>
<span>We want the answer in meters so we need to convert 450nm to meters. </span>
<span>450nm= 4.5 X 10^ -7 m </span>
<span>(3.0 X 10^8 m/s) = (frequency)(4.5 X 10^ -7 m) </span>
<span>Divide the speed of light by the wavelength. </span>
<span>(3.0 X 10^8m/s) / (4.5 X 10^ -7m) =6.67 X 10^ 14 per second or s- </span>
<span>Answer: 6.67 X 10^14 s- hope this helps</span>
The net force acting on the car is 65 N to the left
The net force acting on an object is simply defined as the resultant force acting on the object.
From the question given, we obtained the following data:
- Force applied to the right (Fᵣ) = 250 N
- Force applied to the left (Fₗ) = 315 N
- Net force (Fₙ) =?
The net force acting on the car can be obtained as follow:
Fₙ = Fₗ – Fᵣ
Fₙ = 315 – 250
<h3>Fₙ = 65 N to the left </h3>
Therefore, the net force acting on the car is 65 N to the left
Learn more on net force: brainly.com/question/19549734
