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3 years ago

As food passes through the alimentary canal, the presence of chemical secretions will occur in which order?

Physics

2 answers:

Natalija [7]3 years ago

7 0

The first one....................

Gekata [30.6K]3 years ago

5 0

It's B I took this test on FLVS

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Melanie watched the path a baseball followed after a pitcher threw it. She noticed that the ball traveled horizontally away from

Alex17521 [72]

Answer:gravity

Explanation:

7 0

3 years ago

An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 25 m lower vert

Musya8 [376]

Answer:

x = 5.79 m

Explanation:

given,

mass of the car = 39000 Kg

spring constant = 5.7 x 10⁵ N/m

acceleration due to gravity = 9.8 m/s²

height of the track = 25 m

length of spring compressed = ?

using conservation of energy

potential energy is converted into spring energy

$m g h = \dfrac{1}{2}kx^2$

$x =\sqrt{\dfrac{2 m g h}{k}}$

$x =\sqrt{\dfrac{2\times 39000 \times 9.8 \times 25}{5.7 \times 10^{5}}}$

$x =\sqrt{33.5263}$

x = 5.79 m

the spring is compressed to x = 5.79 m to stop the car.

3 0

3 years ago

We can catch a rolling ball but not a flying bullet?? give reason

Triss [41]

Answer:

yeah this statement is tru

Explanation:

it is because the speed of the bullet is more than the speed of rolling ball .so from this reason we cannot catch a bullet.

3 0

3 years ago

Read 2 more answers

1. Why is only a small portion of the solar energy that strikes Earth's atmosphere stored by primary producers?

DanielleElmas [232]

Explanation:

only a fraction of radiation strikes plants or algae and only a portion of that fraction is of wavelengths suitable for photosynthesis and much energy is lost as a result of reflection or heating of plant tissue

5 0

2 years ago

A student sits in a chair that can spin without friction. The student has her hands outstretched and starts rotating at 1.9 rev/

Airida [17]

Answer:

the resulting angular speed after she pulls her hand inwards in (rad/s) is 27.02 rad/s

Explanation:

Given that :

the initial angular speed $\omega_1 = 1.9 \ \ rev/s$

Initial rotational inertia $I_1 = 12.00 \ \ kg.m^2$

Final angular speed $\omega_2 = ???$

Final rotational inertia $I_2 = 5.3 \ \ kg.m^2$

According to conservation of momentum :

Initial momentum = final momentum

$I_1 \omega_1 = I_2 \omega_2$

$\omega_2 = \frac{I_1 \omega_1}{I_2}$

$\omega_2 = \frac{12.00*1.9}{5.3}$

$\omega_2 = 4,3$ $rev/s$

To rad/s ; we have:

$1 \ rev/s = 2 \pi \ \ rad/s$

$\omega_2 = 4.3 * 2 \pi \ \ rad/s$

$\omega_2 = 27.02 \ \ rad/s$

Therefore the resulting angular speed after she pulls her hand inwards in (rad/s) = 27.02 rad/s

8 0

3 years ago