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2 years ago

1)What is the use of the information obtained from remote sensing camera

Physics

1 answer:

Naya [18.7K]2 years ago

5 0

Answer:

Remote sensing is the process of detecting and monitoring the physical characteristics of an area by measuring its reflected and emitted radiation at a distance ... first question answers

Explanation:

The space shuttle launched like a rocket. But it landed like a glider airplane. The solid rocket boosters and the main engines on the orbiter helped the shuttle blast off from Earth like a rocket. ... The external tank would burn up over Earth......second question answer

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A sound wave has a frequency of 425 Hz. What is the period of this wave

Oduvanchick [21]

Answer: The time period of the given wave with frequency of 425 Hertz is 0.0023 seconds.

Explanation:

Frequency of the wave = 425 Hertz = $425 sec^{-1}$

$\text{Time period}=\frac{1}{Frequency}$

$\text{Time period}==\frac{1}{425 sec^{-1}}=0.0023 sec$

The time period of the given wave with frequency of 425 Hertz is 0.0023 seconds.

5 0

3 years ago

If you change the magnetic field in a closed loop of wire You induce in the loop a(n) A. current. B. voltage. C. electric field.

Luba_88 [7]

d: all of these because more coil will increase the current,voltage,and the electrical field hope this helped

8 0

3 years ago

Read 2 more answers

Electric forces stay the same as distance changes electric field change true or false

Kisachek [45]

Answer:

False

Explanation:

7 0

3 years ago

A concert loudspeaker suspended high off the ground emits 28.0 W of sound power. A small microphone with a 0.700 cm2 area is 55.

grandymaker [24]

Explanation:

It is known that wave intensity is the power to area ratio.

Mathematically, I = $\frac{P}{A}$

As it is given that power is 28.0 W and area is $7 \times 10^{-5} m^{2}$ .

Therefore, sound intensity will be calculated as follows.

I = $\frac{P}{A}$

= $\frac{28.0 W}{4 \times 3.14 \times 7 \times 10^{-5} m^{2}}$

= $0.318 \times 10^{5} W/m^{2}$

or, = $3.18 \times 10^{4} W/m^{2}$

Thus, we can conclude that sound intensity at the position of the microphone is $3.18 \times 10^{4} W/m^{2}$ .

7 0

3 years ago

A heat engine has a maximum possible efficiency of 0.780. If it operates between a deep lake with a constant temperature of-24.8

Volgvan

Answer : The temperature of the hot reservoir (in Kelvins) is 1128.18 K

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used for efficiency of the heat engine.

$\eta =1-\frac{T_c}{T_h}$