Answer:
плщщащмапромплщкутчрралагыд
Answer:
A) and B) are correct.
Explanation:
If the object is at rest, it means that no net force is exerted on it.
As the object experiences a downward gravitational force from Earth, in order to be at rest, it must experience an upward force with the same magnitude as the gravitational force on the object.
This force is supplied by the normal force, which can adopt any value in order to meet the condition imposed by Newton´s 2nd Law, and is always perpendicular to the surface on which the object is placed (in this case, the ground).
At a molecular level, this normal force is supplied by the bonded molecules of the ground that behave like small springs being compressed by the molecules of the object, exerting an upward restoring force upward on them.
So, the statements A) and B) are true.
Answer:
204kW
Explanation:
P = t x ω = 500 x (2πx3900/60) = 204203W = 204kW
Answer:
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
Explanation:
Given that
Yield strength ,Sy= 240 MPa
Tensile strength = 310 MPa
Elastic modulus ,E= 110 GPa
L=380 mm
ΔL = 1.9 mm
Lets find strain:
Case 1 :
Strain due to elongation (testing)
ε = ΔL/L
ε = 1.9/380
ε = 0.005
Case 2 :
Strain due to yielding
ε '=0.0021
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
For computation of load strain due to testing should be less than the strain due to yielding.
Answer:
-2.83 m/s²
Explanation:
- Initial velocity (u) = 34 m/s
- Final velocity (v) = 17 m/s
- Time taken (t) = 6 seconds
❖ Acceleration is defined as the rate of change in velocity with time.
→ a = (v - u)/t
- v denotes final velocity
- a denotes acceleration
- u denotes initial velocity
- t denotes time
→ a = (17 - 34)/6 m/s²
→ a = -17/6 m/s²
<h3>→ Acceleration = -2.83 m/s²</h3>
(Minus sign implies that the velocity is decreasing.)
