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frez [133]
3 years ago
12

Which best illustrates projectile motion

Physics
2 answers:
Gwar [14]3 years ago
6 0

Answer:

its D

Explanation:

took the test

worty [1.4K]3 years ago
3 0

Answer:

D) The guy jumping

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What foods are recommended for pregnant woman?
miss Akunina [59]

Answer:

Vagetagble, fruits,fresh milk and juice vitamins c

3 0
3 years ago
Compare and contrast the energy transfer of a roller coaster to that of a pendulum
Softa [21]

When the pendulum and roller coaster move to the top, its has more potential energy whereas when comes to the bottom has more kinetic energy.

<h3>Compare and contrast the energy transfer of a roller coaster to that of a pendulum:</h3><h3>What is the transfer of energy in a roller coaster?</h3>

The transfer of potential energy to kinetic energy occur when the roller coaster move along the track. As the motor pulls the cars to the top, the body has more potential energy whereas when the body comes to the bottom , it has kinetic energy in the object.

<h3>What is the energy transfer in a pendulum?</h3>

As a pendulum swings, its potential energy changes to kinetic energy and kinetic energy changes into potential energy. At the top more potential energy is present.

So we can conclude that When the pendulum and roller coaster move to the top, its has more potential energy whereas when comes to the bottom has more kinetic energy.

Learn more about energy here: brainly.com/question/13881533

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8 0
2 years ago
What resistance must be connected in parallel with a 633-Ω resistor to produce an equivalent resistance of 205 Ω?
alukav5142 [94]

Answer:

303 Ω

Explanation:

Given

Represent the resistors with R1, R2 and RT

R1 = 633

RT = 205

Required

Determine R2

Since it's a parallel connection, it can be solved using.

1/Rt = 1/R1 + 1/R2

Substitute values for R1 and RT

1/205 = 1/633 + 1/R2

Collect Like Terms

1/R2 = 1/205 - 1/633

Take LCM

1/R2 = (633 - 205)/(205 * 633)

1/R2 = 428/129765

Take reciprocal of both sides

R2 = 129765/428

R2 = 303 --- approximated

5 0
3 years ago
In a certain time interval, natural gas with energy content of 19000 J was piped into a house during a winter day. In the same t
Bumek [7]

Explanation:

Since, it is mentioned the there occurs no change in the temperature. This also means that there will occur no change in thermal energy of the system.

Hence, \Delta E = 0. And, as \Delta E = 0 then there will be no work involved. This means that total energy added to the house will return to the outside air as heat.

Therefore,

                   Q = -(19000 J + 2000 J)

                       = -21000 J

or,    |Q| = 21000 J

Thus, we can conclude that the magnitude of the energy transfer between the house and the outside air is 21000 J.

5 0
3 years ago
Does calm water have a regular reflection or a diffuse reflection
Shtirlitz [24]
A regular relflection
8 0
3 years ago
Read 2 more answers
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