The distance between a charge and the source of an electric field changes from 3 mm to 6 mm. as a result of the change, the elec
1 answer:
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Answer:
6.9066 × 10⁻⁵ m
Explanation:
For constructive interference, the expression is:
Where, m = 1, 2, .....
d is the distance between the slits.
The formula can be written as:
....1
The location of the bright fringe is determined by :
Where, L is the distance between the slit and the screen.
For small angle ,
So,
Formula becomes:
Using 1, we get:
Thus, the distance between the central maximum is 3.00 cm
First bright fringe , m = 1 occur at 3.00 / 2 = 1.50 cm
Since,
1 cm = 0.01 m
y = 0.0150 m
Given L = 2.00 m
λ = 518 nm
Since, 1 nm = 10⁻⁹ m
So,
λ = 518 × 10⁻⁹ m
Applying the formula as:
<u>⇒ d, distance between the slits = 6.9066 × 10⁻⁵ m</u>
Answer:
-1.65
Explanation:
First of all, we find the position of the image by using the lens equation:
where:
f is the focal length of the lens
p is the distance of the object from the lens
q is the distance of the image from the lens
For the lens in this problem:
f = 21.0 cm (the focal length of a convex lens is positive)
p = 33.7 cm
Solving for q, we find the position of the image:
Then, the magnification of the image is given by:
And substituting,
Which means that the image is inverted (negative sign) and enlarged (because M is larger than 1).