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3 years ago

Which of the following points is

Mathematics

1 answer:

stiks02 [169]3 years ago

8 0

The answer is A!!!!!!

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Accidentally checked in help me plz!!!!!!

Sergio [31]

Answer:

It is 1/4!

Step-by-step explanation:

Because if you 4 1/4 will equal 1 now do that until you reach 16 then add two 1/4 then you will get you answer.

Please mark me as Brainiest.

And please let me know if you got it correct im curious.

Thank You!:)

Glad to Help!

BTW sorry if you did not understant my explanation.

4 0

3 years ago

Read 2 more answers

Help me with trigonometry

poizon [28]

Answer:

See below

Step-by-step explanation:

It has something to do with the Weierstrass substitution, where we have

$\int\, f(\sin(x), \cos(x))dx = \int\, \dfrac{2}{1+t^2}f\left(\dfrac{2t}{1+t^2}, \dfrac{1-t^2}{1+t^2} \right)dt$

First, consider the double angle formula for tangent:

$\tan(2x)= \dfrac{2\tan(x)}{1-\tan^2(x)}$

Therefore,

$\tan\left(2 \cdot\dfrac{x}{2}\right)= \dfrac{2\tan(x/2)}{1-\tan^2(x/2)} = \tan(x)=\dfrac{2t}{1-t^2}$

Once the double angle identity for sine is

$\sin(2x)= \dfrac{2\tan(x)}{1+\tan^2(x)}$

we know $\sin(x)=\dfrac{2t}{1+t^2}$ , but sure, we can derive this formula considering the double angle identity

$\sin(x)= 2\sin\left(\dfrac{x}{2}\right)\cos\left(\dfrac{x}{2}\right)$

Recall

$\sin \arctan t = \dfrac{t}{\sqrt{1 + t^2}} \text{ and } \cos \arctan t = \dfrac{1}{\sqrt{1 + t^2}}$

Thus,

$\sin(x)= 2 \left(\dfrac{t}{\sqrt{1 + t^2}}\right) \left(\dfrac{1}{\sqrt{1 + t^2}}\right) = \dfrac{2t}{1 + t^2}$

Similarly for cosine, consider the double angle identity

Thus,

$\cos(x)= \left(\dfrac{1}{\sqrt{1 + t^2}}\right)^2- \left(\dfrac{t}{\sqrt{1 + t^2}}\right)^2 = \dfrac{1}{t^2+1}-\dfrac{t^2}{t^2+1} =\dfrac{1-t^2}{1+t^2}$

Hence, we showed $\sin(x) \text { and } \cos(x)$

======================================================

$5\cos(x) =12\sin(x) +3, x \in [0, 2\pi ]$

Solving

$5\,\overbrace{\frac{1-t^2}{1+t^2}}^{\cos(x)} = 12\,\overbrace{\frac{2t}{1+t^2}}^{\sin(x)}+3$

$\implies \dfrac{5-5t^2}{1+t^2}= \dfrac{24t}{1+t^2}+3 \implies \dfrac{5-5t^2 -24t}{1+t^2}= 3$

$\implies 5-5t^2-24t=3\left(1+t^2\right) \implies -8t^2-24t+2=0$

$t = \dfrac{-(-24)\pm \sqrt{(-24)^2-4(-8)\cdot 2}}{2(-8)} = \dfrac{24\pm 8\sqrt{10}}{-16} = \dfrac{3\pm \sqrt{10}}{-2}$

$t=-\dfrac{3+\sqrt{10}}{2}\\t=\dfrac{\sqrt{10}-3}{2}$

Just note that

$\tan\left(\dfrac{x}{2}\right) = \dfrac{3\pm 8\sqrt{10}}{-2}$

and $\tan\left(\dfrac{x}{2}\right)$ is not defined for $x=k\pi , k\in\mathbb{Z}$

6 0

3 years ago

The dimensions of a parking lot are measured in feet. What units will the area be measured in?

mr Goodwill [35]

Answer:

D) feet²

Step-by-step explanation:

Area = side × side

= feet × feet

= feet²

3 0

3 years ago

Please help! I will mark brianliest!!

fgiga [73]

Answer:

Perimeter: 310 units

Step-by-step explanation:

If x=4 and y=5, then the measure of the lengths would be..

8y+19= 8(5)+19= 59

8x+64= 8(4)+64= 96

13y-6= 13(5)-6= 59

16x+32= 16(4)+32= 96

To check if all these measurements are congruent, we can see if they match up with the measure of their parallel line, which they do in this case because 59=59

96=96

To find the perimeter of any shape, we add all the side lengths together

59+59+96+96= 310

Hope I was able to help! Good Luck!

5 0

3 years ago

Read 2 more answers

Plz help me with it

quester [9]

Answer: $\bold{\sqrt[4]{2} }$