Question

PLS HELP ! Will give brainliest!

Answer 1

Given:

The quadratic equation is :

$16x^2-20x-6=0$

To find:

The quadratic formula for the given equation after substituting the values.

Solution:

If a quadratic equation is $ax^2+bx+c=0$, then the quadratic formula is:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

We have,

$16x^2-20x-6=0$

In this equation, $a=16,b=-20,c=-6$.

Substituting $a=16,b=-20,c=-6$ in the above formula, we get

$x=\dfrac{-(-20)\pm \sqrt{(-20)^2-4(16)(-6)}}{2(16)}$

Therefore, the required quadratic formula for the given equation after substituting the values is $x=\dfrac{-(-20)\pm \sqrt{(-20)^2-4(16)(-6)}}{2(16)}$.