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Oksanka [162]
3 years ago
13

PLS HELP ! Will give brainliest!

Mathematics
1 answer:
Rasek [7]3 years ago
3 0

Given:

The quadratic equation is :

16x^2-20x-6=0

To find:

The quadratic formula for the given equation after substituting the values.

Solution:

If a quadratic equation is ax^2+bx+c=0, then the quadratic formula is:

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

We have,

16x^2-20x-6=0

In this equation, a=16,b=-20,c=-6.

Substituting a=16,b=-20,c=-6 in the above formula, we get

x=\dfrac{-(-20)\pm \sqrt{(-20)^2-4(16)(-6)}}{2(16)}

Therefore, the required quadratic formula for the given equation after substituting the values is x=\dfrac{-(-20)\pm \sqrt{(-20)^2-4(16)(-6)}}{2(16)}.

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