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3 years ago

Square root of 3 what is it

Mathematics

1 answer:

slavikrds [6]3 years ago

6 0

Square root of 3 is 1.732

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Find the solution of 64 = 16u algebraically. please I’m desperate

Sauron [17]

Answer:

u = 4

Step-by-step explanation:

Divide by 16 on both sides. [Division Property of Equality]

64/16 = 16u/16

u = 4

==================================================================Hope I Helped, Feel free to ask any questions to clarify :)

Have a great day!

More Love, More Peace, Less Hate.

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3 0

3 years ago

Complete the square to factor X^2 +10X=-8

ella [17]

Answer: $x=\sqrt{17}-5$ and $x = -\sqrt{17}-5$

Step-by-step explanation:

Alright, lets get started.

The given equation is :

$x^{2} +10x = -8$

Adding 8 in both sides, it will become

$x^{2} +10x + 8 = -8 +8$

$x^{2} +10x + 8 = 0$

To make it perfect square, we need to add 25 and subtract 25

$x^{2} +10x + 8 +25-25= 0$

$x^2+10x+25+8-25=0$

$(x+5)^2+8-25=0$

$(x+5)^2-17=0$

Adding 17 in both sides

$(x+5)^2=17$

taking square root

$x+5=\sqrt{17}$

So,

$x=\sqrt{17}-5$ and $x = -\sqrt{17}-5$ .. Answer

Hope it will help :)

7 0

3 years ago

Read 2 more answers

How do you find the derivative of 1/logx?

valentina_108 [34]

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

$With the chain rule. \\ 1log(x)=log(x)−1 \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\ \\−2⋅ddxlog(x) \\ =−1log(x)21x \\ =−1xlog(x)2 .$