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VladimirAG [237]
3 years ago
6

Solve the equation for X (If possible please show work)

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0

Answer:

the correct answer is x=5

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How to change 45% into a fraction <br> How to change 120% into a fraction
Eddi Din [679]

Answer: 3/25 and 9/20

Step-by-step explanation:

We take the number and covert it into a fraction

A 2 digit Numerator = a 3 digit denominator

A 3 digit Numerator = a 4 digit denominator

And so on...

Then We can reduce,

45/100 = 9/20

120/1000 = 3/25

Hope this helped!

7 0
3 years ago
Pls help it is due today
Arlecino [84]

Answer:

576

Step-by-step explanation:

4 feet^2 = 2 feet*2 feet = 24 inch * 24 inch. 24*24 = 576.

8 0
3 years ago
Read 2 more answers
Solve the triangle. A = 54°, b = 11, c = 8
Delicious77 [7]
In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.

For finding side a, you can answer this easily by the Law of Cosines. The equation is

a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9 

Then, we use the Law of Sines to find angles B and C. The formula would be

a/sinA = b/sinB = c/sinC
9/sin54° =  11/sinB
B = 80.4°

9/sin54° = 8/sinC
C = 45.6°

The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
5 0
3 years ago
Will mark brainly! 20 points please hurry and help!!
Nata [24]
The correct answer is number one, number four, and number five. Please park Brainliest if helpful. Thanks
6 0
3 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
3 years ago
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