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VARVARA [1.3K]
3 years ago
10

An important postulate in geometry states: "Through Point P, there is only one line parallel to ". What is the equation of line

l, parallel to that passes through Point X?
A ( -10,8) B(2,3) X(-5,10)

This is on a graph and I have to show steps and I am stumped
Mathematics
1 answer:
telo118 [61]3 years ago
5 0
At first we will find the slope of the line that <span>passes through the points A and B
</span>
<span>A ( -10,8), B(2,3)
slope = (Δy)/(Δx) = (3-8)/(2-(-10)) = -5/12

the require line is parallel to the line </span><span><span>passes through the points A and B
</span>∴ the slope of the line </span><span>that passes through Point X = -5/12
and have a general form
   y = m x + c
where m is the slope and c is constant
the constant can be calculated by substituting with the point x (-5,10) in the equation of general form
∴ 10 = (-5/12)*-5 + c
   c = 10 - 25/12 = 95/12
∴ y = (-5/12)x +95/12  ⇒⇒⇒⇒ multiplying the equation by 12

∴ 12y = -5x +95 
</span>
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8(5-32) equal to and explain <br> please help
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You would use order of operations: PEMDAS
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with MD and AS order doesnt matter.
8(5-32) you would start with inside the Parenthesis for "P" so (5-32)=(-27)
next you would go to the E but because you dont have an exponent you go to the next step with is the "MD" you have multiplication so next would be 8(-27) and 8 multiplied by -27 is: 8(-27)= -216
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