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VARVARA [1.3K]
4 years ago
10

An important postulate in geometry states: "Through Point P, there is only one line parallel to ". What is the equation of line

l, parallel to that passes through Point X?
A ( -10,8) B(2,3) X(-5,10)

This is on a graph and I have to show steps and I am stumped
Mathematics
1 answer:
telo118 [61]4 years ago
5 0
At first we will find the slope of the line that <span>passes through the points A and B
</span>
<span>A ( -10,8), B(2,3)
slope = (Δy)/(Δx) = (3-8)/(2-(-10)) = -5/12

the require line is parallel to the line </span><span><span>passes through the points A and B
</span>∴ the slope of the line </span><span>that passes through Point X = -5/12
and have a general form
   y = m x + c
where m is the slope and c is constant
the constant can be calculated by substituting with the point x (-5,10) in the equation of general form
∴ 10 = (-5/12)*-5 + c
   c = 10 - 25/12 = 95/12
∴ y = (-5/12)x +95/12  ⇒⇒⇒⇒ multiplying the equation by 12

∴ 12y = -5x +95 
</span>
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A sphere is inscribed in a cube, and the cube has a surface area of 24 square meters. A second cube is then inscribed within the
snow_tiger [21]

Check the picture below, I'll be referring to the material in the picture.

we know the outer cube has a surface area of 24, we also know is a cube, so it has 6 equal sides which are squares each, let's say the side of one of those squares in the cube is say of length "s", so the area of one square will just be  s², and for 6 squares that'll be an area of 6s², that is the area of the outer cube, which we know is 24.

24=6s^2\implies \cfrac{24}{6}=s\implies 4=s^2\implies \sqrt{4}=s\implies 2=s

now, we know the sphere is inscribed in the outer cube, so it's touching its edges, like you see in the picture in blue, so if we get a cross-section of the whole lot, we'd get the picture to the right of blue cube in the picture, an outer cube with a side of 2, and therefore an sphere with a diameter of 2, and thus a radius of 1, as you can see in the red triangle.

Let's notice that the red triangle is a 45-45-90 triangle, and thus we can use the 45-45-90 rule to get its sides, as you can see in the picture on the far-right, which gives us half of one side of the inner cube to be 1/√2.

\stackrel{\textit{half a side}}{\cfrac{1}{\sqrt{2}}}\qquad \stackrel{\textit{a full side}}{\cfrac{1}{\sqrt{2}}+\cfrac{1}{\sqrt{2}}}\implies \cfrac{2}{\sqrt{2}}\implies \cfrac{2\sqrt{2}}{\sqrt{2}\sqrt{2}}\implies \cfrac{2\sqrt{2}}{2}\implies \sqrt{2}

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6 0
2 years ago
How fo you solve the quadratic equation by factoring 3x^2=5x
qaws [65]
Good morning ^ _ ^


3x² = 5x
3x² - 5x = 0
From that part we can factorize
x(3x - 5) = 0
Set factors equal to 0
x = 0 or 3x - 5 = 0
x =0 or 3x = 0 + 5
x = 0 or 3x = 5
x = 0 or x = 5/3

The final answer is : X = 0 or X = 5/3


A+ Guaranteed! 

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