At first we will find the slope of the line that <span>passes through the points A and B </span> <span>A ( -10,8), B(2,3) slope = (Δy)/(Δx) = (3-8)/(2-(-10)) = -5/12
the require line is parallel to the line </span><span><span>passes through the points A and B </span>∴ the slope of the line </span><span>that passes through Point X = -5/12 and have a general form y = m x + c where m is the slope and c is constant the constant can be calculated by substituting with the point x (-5,10) in the equation of general form ∴ 10 = (-5/12)*-5 + c c = 10 - 25/12 = 95/12 ∴ y = (-5/12)x +95/12 ⇒⇒⇒⇒ multiplying the equation by 12