Answer:
The conservation of energy should be used to answer this question.
a)
At the position where the spring is unstretched, the elastic potential energy of the spring is zero.
since 
and 
is equal to zero.
The roots of this quadratic equation can be solved by using discriminant.
We should use the positive root, so
x = 0.292 m.
b)
We should use energy conservation between the point where the spring is momentarily at rest, and the point where the spring is unstretched.
since the kinetic energy at point 2 and the potential energy at point 3 is equal to zero.
Explanation:
In questions with springs, the important thing is to figure out the points where kinetic or potential energy terms would be zero. When the spring is unstretched, the elastic potential energy is zero. And when the spring is at rest, naturally the kinetic energy is equal to zero.
In part b) the cookie slides back to its original position, so the distance traveled, x, is equal to the distance in part a). The frictional force is constant in the system, so it is quite simple to solve part b) after solving part a).
Your break probably only took 20-30 minutes. Bacteria can double every 20-30 minutes. Hope this helped!
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Before collecting a specimen of urine or feces, the nursing assistant asks the nurse or consults the lab for which storage and delivery method to use.
There are different tests that need to be performed on a urine or feces specimen. It depends on the patients that which test would be asked for him to be done.
The storage and delivery methods for urine and feces in the case of different tests has to be consulted by the nurse or consultant.
Incase of an emergency test, whose results are immediately required the method of delivery is a fast mode one. For patients that have a mild disease or are not at risk, other reliable methods can be used. Each specimen should be properly labeled for proper checking.
To learn more about urine specimen, click here:
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Work done=mgh
W=force*height
W=5N*0.50mts
W=2.5joule
Answer:
Explanation:
Given that,
Orbital period, T = 42.5 hours = 153000 seconds
The average distance of Jupiter's mass, r = 422,000 km
We need to find Jupiter's mass. The formula for the orbital period is given by :
So, the mass of Jupiter is 
.
