Answer:
Avg.velocity=(Δy/ Δt) =(net displacement/ total time for journey)
Δy = 0
Δt = t
so avg. velocity = 0/t =0
Avg. speed =(total distance traveled/ total time for journey)
total distance = up +down = Ymax+Ymax= 2 Ymax
total time = t
avg. speed = 2 Ymax/t
Explanation:
Since there is no net displacement from the original position,velocity is zero. Claudia is right!
while it covered some distance in time t so its speed is not as qouted by Hossien
Answer:
The correct answer is V√5
Explanation:
Let V be the velocity of the satellite orbiting at radius r.
Let V(5r) be the velocity of the satellite orbiting at radius 5r.
Recall:
Escape velocity is given by:
V = √(2gr)
Where V is the escape velocity
g is the acceleration due to gravity
r is the radius of the earth.
With the above equation, we can obtain the answer to the question as follow:
V = √(2gr)
V(5r) = √(2g5r)
Next, we'll obtained the ratio of V(5r) to V as shown below
V(5r) : V => V(5r)/V
V(5r)/V = √(2g5r) / √(2gr)
V(5r)/V = √5
Cross multiply
V(5r) = V√5
From the above illustration, we can see that when the satellite is moved to 3r, then the expression for the velocity will be V√5
<span>1 pound is equal to .454 kilograms.
115 pounds equals
115 x .454 kilograms = 52.163 kg.
The total dose is equal to the dose per kilograms multiplied by the total mass in kilograms.
6.00mg/kg x 52.163kg = 312.978mg.
The total dose is 313.0 mg</span>
Answer:A is the answer
Explanation: I know it's late but here you go
