Unlike a ball, an atom doesn't have a fixed radius. The radius of an atom can only be found by measuring the distance between the nuclei of two touching atoms, and then halving that distance... Does that answer your question?
Answer:
7.08 m/s²
Explanation:
Given:
v₀ = 20.0 m/s
v = 105 m/s
t = 12.0 s
Find: a
v = at + v₀
105 m/s = a (12.0 s) + 20.0 m/s
a = 7.08 m/s²
Answer:
X₃₁ = 0.58 m and X₃₂ = -1.38 m
Explanation:
For this exercise we use Newton's second law where the force is the Coulomb force
F₁₃ - F₂₃ = 0
F₁₃ = F₂₃
Since all charges are of the same sign, forces are repulsive
F₁₃ = k q₁ q₃ / r₁₃²
F₂₃ = k q₂ q₃ / r₂₃²
Let's find the distances
r₁₃ = x₃- 0
r₂₃ = 2 –x₃
We substitute
k q q / x₃² = k 4q q / (2-x₃)²
q² (2 - x₃)² = 4 q² x₃²
4- 4x₃ + x₃² = 4 x₃²
5x₃² + 4 x₃ - 4 = 0
We solve the quadratic equation
x₃ = [-4 ±√(16 - 4 5 (-4)) ] / 2 5
x₃ = [-4 ± 9.80] 10
X₃₁ = 0.58 m
X₃₂ = -1.38 m
For this two distance it is given that the two forces are equal
We have to choose the correct name for the zone along the southern margins of the Sahara. Laterite is a soil in hot and wet tropical areas. Savanna is the tropical grassland. It has tropical savanna climate. Veldt is name for the areas in the South Africa. Finally, the Sahel is the zone along the south margins of the Sahara. It has a semi-arid climate. The Arabic word "sahel" means "coast". Answer: C. Sahel. <span> </span>
As per energy conservation in the reversible engine we can say
![Q_2 + W = Q_1](https://tex.z-dn.net/?f=Q_2%20%2B%20W%20%3D%20Q_1)
here we know that
![Q_2 = 3300 kJ/h](https://tex.z-dn.net/?f=Q_2%20%3D%203300%20kJ%2Fh)
![Q_1 = 4800 kJ/h](https://tex.z-dn.net/?f=Q_1%20%3D%204800%20kJ%2Fh)
now from above equation
![3300 + W = 4800](https://tex.z-dn.net/?f=3300%20%2B%20W%20%3D%204800)
![W = 1500 kJ/h](https://tex.z-dn.net/?f=W%20%3D%201500%20kJ%2Fh)
now we can convert it into kW
![W = 1500\times \frac{kJ}{3600s}](https://tex.z-dn.net/?f=W%20%3D%201500%5Ctimes%20%5Cfrac%7BkJ%7D%7B3600s%7D)
![W = 0.42 kW](https://tex.z-dn.net/?f=W%20%3D%200.42%20kW)
so above is the power input to the refrigerator
now to find COP we know that
![COP = \frac{Q_2}{W}](https://tex.z-dn.net/?f=COP%20%3D%20%5Cfrac%7BQ_2%7D%7BW%7D)
![COP = \frac{3300}{1500} = 2.2](https://tex.z-dn.net/?f=COP%20%3D%20%5Cfrac%7B3300%7D%7B1500%7D%20%3D%202.2)
so COP of refrigerator is 2.2