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Bogdan [553]
3 years ago
9

2. A body moves with a uniform speed of 1.5 ms-1 for 20 seconds. Find the distance covered by it.

Physics
1 answer:
mestny [16]3 years ago
7 0

Answer:

30 m

Explanation:

The speed is uniform, so there's no acceleration.  Therefore:

Distance = rate × time

d = 1.5 m/s × 20 s

d = 30 m

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A satellite at a particular point along an elliptical orbit has a gravitational potential energy of 5100 MJ with respect to Eart
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To solve this problem we will apply the theorem given in the conservation of energy, by which we have that it is conserved and that in terms of potential and kinetic energy, in their initial moment they must be equal to the final potential and kinetic energy. This is,

E_{initial} = E_{final}

PE_{initial}+KE_{initial} = PE_{final}+KE_{final}

Replacing the 5100MJ for satellite as initial potential energy, 4200MJ for initial kinetic energy and 5700MJ for final potential energy we have that

KE_{final} = (PE_{initial}+KE_{initial} )-PE_{final}

KE_{final} = (5100+4200)-5700

KE_{final} = 3600MJ

Therefore the final kinetic energy is 3600MJ

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A body of mass 500kg moving at a speed of 10m/s reaches the speed of 50m/s in 20s.The force exerted is
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Answer:

answer is 1000 N

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Explain how the global sea surface temperature is affected by solar activity.
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The higher the solar activity, and the hotter it is, the more the oceans heat up and water evaporates into the atmosphere. High amounts of water vapor causes things like hurricanes. However, oceans have a high absorption rate of heat so they can absorb a lot of it without heating up the atmosphere, which is pretty good or else the Earth would overheat.
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By means of a rope whose mass is negligible, two blocks are suspended over a pulley, as the drawing shows, with m1 = 12.1 kg and
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Answer:

14.8 kg

Explanation:

We are given that

m_1=43.7 kg

m_2=12.1 kg

g=9.8 m/s^2

a=\frac{1}{2}(9.8)=4.9 m/s^2

We have to find the mass of the pulley.

According to question

T_2-m_2 g=m_2 a

T_2=m_2a+m_2g=m_2(a+g)=12.1(9.8+4.9)=177.87 N

T_1=m_1(g-a)=43.7(9.8-4.9)=214.13 N

Moment of inertia of pulley=I=\frac{1}{2}Mr^2

(T_2-T_1)r=I(-\alpha)=\frac{1}{2}Mr^2(\frac{-a}{r})=\frac{1}{2}Mr(-4.9)

Where \alpha=\frac{a}{r}

(177.87-214.13)=-\frac{1}{2}(4.9)M

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M=\frac{36.26\times 2}{4.9}=14.8 kg

Hence, the mass of the pulley=14.8 kg

6 0
3 years ago
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