Answer:
354200J
Explanation:
Given parameters:
Mass of copper bushing = 8kg
Initial temperature = 25°C
Final temperature = 140°C
Unknown:
Quantity of heat required to heat this mass = ?
Solution:
The amount of heat required to heat mass from one temperature to another is given by;
H = m c Δt
where m is the mass
c is the specific heat
Δt is the change in temperature
C is a constant and for copper, its value is 385J/kg°C
Input the parameters;
H = 8 x 385 x (140 - 25) = 354200J
Answer:
Explanation:
1. What are the forces acting on the block when it is hanging freely from the spring scale? What is the net force on the block? What are the magnitudes of each of the forces acting on the block? Explain.
When a block is hanging freely, two forces are acting on it = tension force from the spring scale and gravity force on the block itself. The net force is zero as the block is not accelerating. The magnitudes of tension and gravity force are the same but in opposite directions.
2. What are the forces that act on the block when it is placed on the ramp and is held in place by the spring scale? What is the net force acting on the block? Explain. (Assume that the ramps are frictionless surfaces.)
There are three forces acting on the block when it is placed on the ramp and is held in place by the spring scale: as in 1, there are tension and gravity but there is a third force - reaction force from the ramp surface on the block that is perpendicular to the surface. Again the block is not moving so the net force is zero.
3. What is the magnitude of normal force acting on the block when it is resting on the flat surface? How does the normal force change as the angle of the ramp increases? Explain. (Assume that the ramps are frictionless surfaces.)
On flat surface, the normal force is equal to the gravity force of the block i.e. its weight. On a vertical surface, the normal force is equal to zero. For the angle of ramp, θ, the normal force = weight * cos θ.
Answer:
Procyon appears brighter in the sky
Explanation:
Apparent magnitude of star Antares = 1.0
Apparent magnitude of star Procyon = 0.4
Pogson's Ratio
m₂-m₁ = -2.50 log(B₂/B₁)
where, m is the apparent magnitude
B = Brightness of star or flux coming towards us (W/m²)
∴Larger magnitudes correspond to fainter stars so here 1>0.4 which means Antares appears dimmer and Procyon appears brighter.
Explanation :
It is given that, a heavy box is in the back of a truck and the truck is accelerating to the right.
The description is shown in<em> figure 1</em>. Here, the forces that act on both box and the truck are the normal force, the frictional force and their weight mg.
The free body diagram is shown in <em>figure 2</em>. This shows the total forces ( F = ma )acting on the truck. As a result, the truck will move in a forward direction.
Hence, this is the required explanation.
Tetraphosphorus disulfide
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