This has alot of information missing. Can you please repost this with more detailed information? Thanks.
Answer:
m < 1 = 18°
Step-by-step explanation:
If <ABD = 72°, and m < 2 is three times the measure of m < 1, then:
Let < ABC = m < 1 = x
< CBD = m < 2 = 3x
We can set up the following formula, since the sum of the measures of angles < 1 and < 2 is equal to <ABD (72°):
m < 1 + m < 2 = < ABD
x + 3x = 72°
Add like terms:
4x = 72°
Divide both sides by 4 to solve for x:

x = 18
Since x = 18, and m < 1 = x , then m < 1 = 18°.
And since m < 2 = 3x, then m < 2 = 3(18°) = 54°.
Let's check to see whether we derived the correct answers by plugging in the values of m < 1 and m < 2 into the established formula:
m < 1 + m < 2 = < ABD
18° + 54° = 72°
72° = 72° (True statement).
Please mark my answers as the Brainliest if my explanations were helpful :)
X^2 + y^2 = 8
X-y=0 so x = y
replace x = y into X^2 + y^2 = 8
y^2 + y^2 = 8
2y^2 = 8
y^2 = 8/2
y^2 = 4
y = - 2 and y = 2
because x = y
so x = - 2 and x = 2
solutions:
x= - 2 and x = + 2
y= - 2 and y = + 2
Given the quadratic function, to get the roots we factorize:
3x²-4x-7=0
3x²+3x-7x-7=0
3x(x+1)-7(x+1)=0
(3x-7)(x+1)=0
thus the roots are
x=-1 or x=3/7
thus the sum of the roots will be:
-1+3/7
=-4/7
Is there supposed to be a attached file? Or are you confused about the topic in general. I can help if need be. I’ll start off with saying that a system of equation is two equations that either have infinite, no, or one solution. This solution makes x true for both equations. x will be the same value for each equation.