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erma4kov [3.2K]
3 years ago
13

What is the molar solubility of magnesium fluoride in a solution that is 0.40 m f− ions? the ksp of mgf2 is 6.4 × 10−9.?

Physics
1 answer:
Margarita [4]3 years ago
6 0
The solubility constant or the Ksp is calculated from the product of the equilibrium concentration of the ions involved. For the compound above, the dissociation would be as follows:

MgF2 = Mg2+ + 2F-1

Ksp = [Mg2+][F-1]^2
6.4x10^-9 = x(2x)^2
x = 1.17x10^-3 mol/L
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"A hiker starts at point P and walks 2.0 kilometers due east and then 1.4 kilometers due north. The vectors in the diagram below
Law Incorporation [45]
Here, you need to use your "Protractor" as it is given in the question, but we can calculate the value with the help of our mathematical calculation too:
[ Protractor can be use only in real life, not here ]

Draw an imaginary line from initial position to final position.
Now, In that triangle, tan x = P/B
tan x = 1.4 / 2
tan x = 0.70
x = tan⁻¹ (0.70)
x = 35  [ tan 35 = 0.70 ]

In short, Your Answer would be 35 degrees

Hope this helps!
3 0
3 years ago
The mass of an object is 60kg on the surface of the earth what will be its weight on the surface of the moon
iris [78.8K]

Answer:

Wm = 97.2 [N]

Explanation:

We must make it clear that mass and weight are two different terms, the mass is always preserved that is to say this will never vary regardless of the location of the object. While weight is defined as the product of mass by gravitational acceleration.

W = m*g

where:

m = mass = 60 [kg]

g = gravity acceleration = 10 [m/s²]

But in order to calculate the weight of the body on the moon, we must know the gravitational acceleration of the moon. Performing a search of this value on the internet, we find that the moon's gravity is.

gm = 1.62 [m/s²]

Wm = 60*1.62

Wm = 97.2 [N]

8 0
3 years ago
A given individual is unable to see objects clearly when he is beyond 60 cm. What power lens should be used to correct this prob
Sveta_85 [38]

Answer:

correct option is E

power lens is - 1.667 D

Explanation:

Given data

infinity = 60 cm

to find out

power lens

solution

we know here infinity v = -60 cm because object at infinity

and we take u  = - infinity

so we know that

1/f = 1/v - 1/u

1/f = 1 / -60  - 1 / -infinity

so

1/f = - 1/60

f = - 60 cm = 0.60 m

and we know power of lens = 1/f

so here

power = 1 / -0.60

power = - 1.667 D

so correct option is E

power lens is - 1.667 D

6 0
4 years ago
A question for the physicists out there:
Tomtit [17]
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7 0
4 years ago
Click through the images and select the model that best shows how J.J. Thomson envisioned the atom.
Alexandra [31]

Answer:

The first one with the big plus in the middle and negatively charged electrons around.

Explanation:

7 0
3 years ago
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