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Nezavi [6.7K]
3 years ago
12

The mass of an object is 60kg on the surface of the earth what will be its weight on the surface of the moon

Physics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

Wm = 97.2 [N]

Explanation:

We must make it clear that mass and weight are two different terms, the mass is always preserved that is to say this will never vary regardless of the location of the object. While weight is defined as the product of mass by gravitational acceleration.

W = m*g

where:

m = mass = 60 [kg]

g = gravity acceleration = 10 [m/s²]

But in order to calculate the weight of the body on the moon, we must know the gravitational acceleration of the moon. Performing a search of this value on the internet, we find that the moon's gravity is.

gm = 1.62 [m/s²]

Wm = 60*1.62

Wm = 97.2 [N]

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Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =
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Answer:

The current is  I  = 8.9 *10^{-5} \  A

Explanation:

From the question we are told that

     The  radius is r =  3.17 \  mm  =  3.17 *10^{-3} \ m

      The current density is  J =  c\cdot r^2  =  9.00*10^{6}  \ A/m^4 \cdot r^2

      The distance we are considering is  r =  0.5 R  =  0.001585

Generally current density is mathematically represented as

          J  =  \frac{I}{A }

Where A is the cross-sectional area represented as

         A  =  \pi r^2

=>      J  =  \frac{I}{\pi r^2  }

=>    I  =  J  *  (\pi r^2 )

Now the change in current per unit length is mathematically evaluated as

        dI  =  2 J  *  \pi r  dr

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

         I  = 2\pi  \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr

         I  = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr

        I  = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ]  | \left    0.001585} \atop 0}} \right.

        I  = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]

substituting values

        I  = 2 *  3.142  *  9.00 *10^6 *   [ \frac{0.001585^4}{4} ]

        I  = 8.9 *10^{-5} \  A

5 0
4 years ago
A ball is launched horizontally at 150 m/s from a cliff. What is its horizontal velocity after 3 seconds? A. 0 m/s B. 30 m/s C.
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Answer:

50m/s

Explanation:

Formula:

velocity= distance/ time

velocity= 150/ 3

velocity= 50 m/s

I hope this helped you :)

7 0
3 years ago
It took 2.5 hours for the bus to travel the distance between two cities at a velocity of 75.0 miles/hr. How many miles lie betwe
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Velocity of the bus = 75 miles/hr
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The distance between the two cities is 187.5 miles.I hope this answer is what you were looking for. This process is applicable for similar problems. In future you can always use this method to determine the answer.

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Answer:

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an oxygen sensor detects te amount of oyen in an engine at the exhaust pipe.

if the  oxygen sensor detects oxygen at the above boundary condition, ten the engine is in good working condition

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